Fibonacci Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11587   Accepted: 8229 Description In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn − 1 + Fn − 2 for n ≥ 2. For example, the first ten terms of the Fibonacci sequenc…

典型的两道矩阵快速幂求斐波那契数列 POJ 那是 默认a=0,b=1 UVA 一般情况是 斐波那契f(n)=(n-1)次幂情况下的(ans.m[0][0] * b + ans.m[0][1] * a): //POJ #include <cstdio> #include <iostream> using namespace std; ; struct matrix { ][]; }ans, base; matrix multi(matrix a, matrix b) { matrix…

Fibonacci Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9650   Accepted: 6856 Description In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn − 1 + Fn − 2 for n ≥ 2. For example, the first ten terms of the Fibonacci sequence…

矩阵乘法裸题 求快速幂 #include<iostream> #include<cstdio> #define ll long long #define Mod 10000 using namespace std; struct node { ][]; }ans,base; node mul(node a,node b) { node tmp; ;i<;i++) ;j<;j++) { tmp.m[i][j]=; ;k<;k++) { tmp.m[i][j]=(tm…