POJ 3281 Dining (网络流之最大流)】的更多相关文章

题意:农夫为他的 N (1 ≤ N ≤ 100) 牛准备了 F (1 ≤ F ≤ 100)种食物和 D (1 ≤ D ≤ 100) 种饮料.每头牛都有各自喜欢的食物和饮料, 而每种食物或饮料只能分配给一头牛.最多能有多少头牛可以同时得到喜欢的食物和饮料? 析:是一个经典网络流的题,建立一个超级源点,连向每种食物,建立一个超级汇点,连向每种饮料,然后把每头牛拆成两个点, 一个和食物连,一个和饮料连,最后跑一遍最大流即可. 代码如下: #pragma comment(linker, "/STACK:…
题意很简单:JOHN是一个农场主养了一些奶牛,神奇的是这些个奶牛有不同的品味,只喜欢吃某些食物,喝某些饮料,傻傻的John做了很多食物和饮料,但她不知道可以最多喂饱多少牛,(喂饱当然是有吃有喝才会饱) 输入数据有N,F,D,表示牛的个数,食物的数量,饮料的数量 接着输出N行表示N个牛的数据 每个牛的数据前2个是Fi和Di表示第i个牛喜欢吃的食物种数和饮料种数,接着输出Fi个食物的编号和Di个食物的编号 ok题意就是这样,这题主要考的是建图 需要把牛拆点,一分为二 图应该是 这种形式      源…
B - DiningTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=88038#problem/B Description Cows are such finicky eaters. Each cow has a preference for certain foods and drinks, and she will consume no oth…
[题意]有F种食物和D种饮料,每种食物或饮料只能供一头牛享用,且每头牛只享用一种食物和一种饮料.现在有N头牛,每头牛都有自己喜欢的食物种类列表和饮料种类列表,问最多能使几头牛同时享用到自己喜欢的食物和饮料. (1 <= F <= 100, 1 <= D <= 100, 1 <= N <= 100) [建模方法] 此题的建模方法比较有开创性.以往一般都是左边一个点集表示供应并与源相连,右边一个点集表示需求并与汇相连.现在不同了,供应有两种资源,需求仍只有一个群体,怎么办?…
题目链接 题意 有\(N\)头牛,\(F\)个食物和\(D\)个饮料.每头牛都有自己偏好的食物和饮料列表. 问该如何分配食物和饮料,使得尽量多的牛能够既获得自己喜欢的食物又获得自己喜欢的饮料. 建图 在 源点 到 食物 之间加边,边权为\(1\) 在 饮料 到 汇点 之间加边,边权为\(1\) 将牛拆成两点,在两点之间加边,边权为\(1\) 这一点很重要,可以从以下两个方面去考虑: 1) 从含义上,只要流为1,这头牛就被满足了,多了就纯属是浪费. 2) 从操作上,最后答案是根据最大流的值来判断的…
Cows are such finicky eaters. Each cow has a preference for certain foods and drinks, and she will consume no others. Farmer John has cooked fabulous meals for his cows, but he forgot to check his menu against their preferences. Although he might not…
Cows are such finicky eaters. Each cow has a preference for certain foods and drinks, and she will consume no others. Farmer John has cooked fabulous meals for his cows, but he forgot to check his menu against their preferences. Although he might not…
POJ 3281 Dining (网络流) Description Cows are such finicky eaters. Each cow has a preference for certain foods and drinks, and she will consume no others. Farmer John has cooked fabulous meals for his cows, but he forgot to check his menu against their…
POJ 3281 Dining id=3281" target="_blank" style="">题目链接 题意:n个牛.每一个牛有一些喜欢的食物和饮料.每种食物饮料仅仅有一个.问最大能匹配上多少仅仅牛每一个牛都能吃上喜欢的食物和喜欢的饮料 思路:最大流.建模源点到每一个食物连一条边,容量为1,每一个饮料向汇点连一条边容量为1,然后因为每一个牛有容量1.所以把牛进行拆点.然后食物连向牛的入点,牛的出点连向食物,跑一下最大流就可以 代码: #incl…
Description Cows are such finicky eaters. Each cow has a preference for certain foods and drinks, and she will consume no others. Farmer John has cooked fabulous meals for his cows, but he forgot to check his menu against their preferences. Although…