Problem description: Georgia and Bob 在玩一个游戏. 如图所示,排成直线的格子上放有n个棋子.棋子 i 在左数第 Pi 个格子上.Georgia 和 Bob 轮流选择一个棋子向左移动.每次可以移动一格及以上任意多格,但是不允许反超其他的棋子,也不允许将两个棋子放在同一格子内.无法进行移动操作的一方失败,假设Georgia 先移动,当双方都采取最优策略时,谁会获胜? 1<=n<=1000 1<=Pi<=10000 Input: n = 3: p =…

Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 9771   Accepted: 3220 Description Georgia and Bob decide to play a self-invented game. They draw a row of grids on paper, number the grids from left to right by 1, 2, 3, ..., and place N ch…

Alice and Bob Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 147    Accepted Submission(s): 22 Problem Description As you know, Alice and Bob always play game together, and today they get a…

Description Alice和Bob在玩游戏.有n个节点,m条边(0<=m<=n-1),构成若干棵有根树,每棵树的根节点是该连通块内编号最 小的点.Alice和Bob轮流操作,每回合选择一个没有被删除的节点x,将x及其所有祖先全部删除,不能操作的人输 .注:树的形态是在一开始就确定好的,删除节点不会影响剩余节点父亲和儿子的关系.比如:1-3-2 这样一条链 ,1号点是根节点,删除1号点之后,3号点还是2号点的父节点.问有没有先手必胜策略.n约为10w. 显然只要算出每颗子树的sg值就可以…

Alice and Bob Time Limit: 1000ms   Memory limit: 65536K 题目描述 Alice and Bob like playing games very much.Today, they introduce a new game. There is a polynomial like this: (a0*x^(2^0)+1) * (a1 * x^(2^1)+1)*.......*(an-1 * x^(2^(n-1))+1). Then Alice as…

Alice and BobTime Limit: 1 Sec  Memory Limit: 64 MBSubmit: 255  Solved: 43 Description Alice is a beautiful and clever girl. Bob would like to play with Alice. One day, Alice got a very big rectangle and wanted to divide it into small square pieces.…

http://acm.sdut.edu.cn/sdutoj/problem.php?action=showproblem&problemid=2608 Alice and Bob Time Limit: 1000ms   Memory limit: 65536K  有疑问?点这里^_^ 题目描述 Alice and Bob like playing games very much.Today, they introduce a new game. There is a polynomial li…

Alice and Bob Time Limit : 10000/5000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 5   Accepted Submission(s) : 1 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Alice and Bob's game nev…

译者注: Bob大叔14年后再次谈论极限编程.极限编程经历了14年的风风雨雨后,Bob大叔将会给它怎么样的定义那? 在我手中拿着的一本白皮薄书,在14年前彻底的改变了软件世界.这本书的标题是解析极限编程,副标题是拥抱变化.作者是Kent Beck,出版时间为1999年. 这本书很薄,不到200页.排版很宽,间隔很远.写作风格即自由散漫又平易近人.章节不多,概念简单. 但是其影响却像地震一样,甚至至今震动仍未平息下来. 起始于第53页的章节10,列出了12项实践,引爆了行业内的大辩论.并催生了一场…

题目链接: Bob and Alice are playing numbers DESCRIPTION Bob and his girl friend are playing game together.This game is like this: There are nn numbers. If op = 11,Bob wants to find two numbers aiai and ajaj,that aiai & ajaj will become maximum value. If…