Exponentiation Time Limit: 2000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9107    Accepted Submission(s): 2654 Problem Description Problems involving the computation of exact values of very large magnitude…

大菲波数 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 16257    Accepted Submission(s): 5403 Problem Description Fibonacci数列,定义如下:f(1)=f(2)=1f(n)=f(n-1)+f(n-2) n>=3.计算第n项Fibonacci数值.   Input 输入第一行…

Game of Connections Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4246    Accepted Submission(s): 2467 Problem Description This is a small but ancient game. You are supposed to write down the…

How Many Fibs? Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3098    Accepted Submission(s): 1232 Problem Description Recall the definition of the Fibonacci numbers:  f1 := 1  f2 := 2  fn :=…

Integer Inquiry Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 9376    Accepted Submission(s): 2406 Problem Description One of the first users of BIT's new supercomputer was Chip Diller. He ex…

Problems involving the computation of exact values of very large magnitude and precision are common. For example, the computation of the national debt is a taxing experience for many computer systems. This problem requires that you write a program to…

import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); BigInteger a,b; while(in.hasNext()) { a = in.nextBigInteger(); b = in.nextBigInteger(); //四则运算 Sy…

e.g. HDU1002 简单加法 import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner cin=new Scanner(System.in); int t=cin.nextInt(); cin.nextLine(); ; ) { t--; String s1=cin.next(); String s2=…

java求两个数中的大数 java中的max函数在Math中 应用如下: int a=34: int b=45: int ans=Math.max(34,45); 那么ans的值就是45.…

题意:给定数字A和数字B,问是否满足gcd(A,B)==1. 思路:可以直接写函数gcd.也可以用大数自带的gcd功能. 代码1: /* @author nimphy @create 2019-11-06-12:07 about: */ import java.io.*; import java.util.*; public class CF1245 { public static void main(String[] args) { Scanner In=new Scanner(System.…