Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Follow up: Can you solve it without using extra space? 这个求单链表中的环的起始点是之前那个判断单链表中是否有环的延伸,可参见我之前的一篇文章 (http://www.cnblogs.com/grandyang/p/4137187.html). 还是要设…
Given a linked list, return the node where the cycle begins. If there is no cycle, return null. To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where tail connects to.…
题目要求 Linked List Cycle Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using extra space? 如何判断一个单链表中有环? Linked List Cycle II Given a linked list, return the node where the cycle begins. If there is no cycle…
题目: Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using extra space? 题解: 这道题连带着II是很经典的,在看CC150时候,纠结这个问题纠结了很久.在读了很多网上资料还有书的讲解以及和别人讨论之后,对这个专题终于明白了. 这一问只需要判断链表是否有环. 当链表没有环时是很好判断的,让一个指针一直往后走,遇见null了自然就没有环. 而如…
Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Follow up:Can you solve it without using extra space? 思路: 做过,就当复习了. 先用快慢指针判断相交,关键是环开始点的获取. 用上图说明一下,设非环的部分长度为a(包括环的入口点), 环的长度为b(包括环的入口点). 快慢指针相交的位置为绿色的点,距离…
Linked List Cycle II Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Follow up:Can you solve it without using extra space? SOLUTION 1: 1. 先用快慢指针判断是不是存在环. 2. 再把slow放回Start处,一起移动,直到二个节点相遇,就是交点.…
Given a linked list, determine if it has a cycle in it. Follow up:Can you solve it without using extra space? 题目大意:给定一个链表,判断是否有环? 解题思路: 解法一:快慢指针,如果有环,那么快慢指针总会相遇,有环:否则快的遍历完整个链表,无环. 解法二:HashSet保存节点,如果下一个节点在set中出现过,那么有环,否则直到遍历完整个链表,无环. Talk is cheap>>…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given a linked list, determine if it has a cycle in it. Follow up: Can you solve it without using extra space? (二)解题 本题大意:给定一个链表,判断链表里面是否成环.不能用辅助空间. 解题思路:利用快…