题意:给出n个数,和一个数p,问你在知道 x%ai  的情况下,能不能确定x%p的值 结论:当n个数的最小公倍数是p的倍数时,可以确定 代码: #include <bits/stdc++.h> #define ll long long using namespace std; const int maxn=1e6+10; vector<int>ve; int n,p; int main() { scanf("%d %d",&n,&p); for(…

D - Remainders Game Description Today Pari and Arya are playing a game called Remainders. Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value . There are n ancient numbersc1,  c2, ..., cn and Pari has to…

题目链接: D. Remainders Game time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Today Pari and Arya are playing a game called Remainders. Pari chooses two positive integer x and k, and tells Arya …

time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard output Today Pari and Arya are playing a game called Remainders. Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to fin…

E. Sum of Remainders 题目连接: http://www.codeforces.com/contest/616/problem/E Description The only line contains two integers n, m (1 ≤ n, m ≤ 1013) - the parameters of the sum. input The only line contains two integers n, m (1 ≤ n, m ≤ 1013) - the para…

D. Remainders Game 题目连接: http://www.codeforces.com/contest/688/problem/D Description Today Pari and Arya are playing a game called Remainders. Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value . There…

B. Remainders Game time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Today Pari and Arya are playing a game called Remainders. Pari chooses two positive integer x and k, and tells Arya k but…

E. Sum of Remainders time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Calculate the value of the sum: n mod 1 + n mod 2 + n mod 3 + ... + n mod m. As the result can be very large, you shoul…

题目链接:http://codeforces.com/problemset/problem/616/E 题意很简单就不说了. 因为n % x = n - n / x * x 所以答案就等于 n * m - (n/1*1 + n/2*2 ... n/m*m) 在根号n复杂度枚举x,注意一点当m>n时,后面一段加起来就等于0,就不用再枚举了. 中间一段x1 ~ x2 的n/x可能相等,所以相等的一段等差数列求和. //#pragma comment(linker, "/STACK:102400…

题目链接: 题目 D. Remainders Game time limit per test 1 second memory limit per test 256 megabytes 问题描述 Today Pari and Arya are playing a game called Remainders. Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the v…