HDU 1007(套圈 最近点对距离)】的更多相关文章

题意是求出所给各点中最近点对的距离的一半(背景忽略). 用分治的思想,先根据各点的横坐标进行排序,以中间的点为界,分别求出左边点集的最小距离和右边点集的最小距离,然后开始合并,分别求左右点集中各点与中间点的距离,从这些距离与点集中的最小距离比较,求得最小距离,此处可按纵坐标排序,将纵坐标距离已经大于之前最小距离的部分都剪枝. 代码如下: #include <bits/stdc++.h> using namespace std; ]; struct point { double x,y; }p[…
Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 25335    Accepted Submission(s): 6716 Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat…
题意: 给出平面上的n个点,问任意点对之间的最短距离是多少? 思路: 先将所有点按照x坐标排序,用二分法将n个点一分为二个部分,递归下去直到剩下两或一个点.对于一个部分,左右部分的答案分别都知道,那么可能的答案就是min(left_ans,right_ans) .注意更小的点对可能一个在左,一个在右.所以还得处理两个边内的紧靠着的部分,如果左边的一个点到达中线的距离已经超过当前最短距离,那么这个点到达右边任意一个点也不会是最短距离了.同时,若一左一右的两个点的y距离已经超过目前最短距离,那么也不…
题目大意:给定平面上的 n 个点,求距离最近的两个点的距离的一半. n <= 10^5.   晕乎乎的度过了一上午... 总之来学习下分治吧233 分治就是把大问题拆成小问题,然后根据对小问题处理出的结果合并成大问题的答案 比如说这道题,如果我们按照X坐标把所有的点分成两组: (木哈哈请叫我盗图狂魔○( ^皿^)っHiahiahia… 像上面我们把点分成了集合S1,S2 点对对应的被划分成3种:S1内,S2内,跨S1.S2 那假若我们分别处理出了S1,S2内的答案,再取个min叫做d 那么跨过分…
思路: 分治 套路题 //By SiriusRen #include <cmath> #include <cstdio> #include <algorithm> using namespace std; ; typedef double db; int n; struct P{db x,y;P(){}P(db X,db Y){x=X,y=Y;}}p[N],t[N]; P operator-(P a,P b){return P(a.x-b.x,a.y-b.y);} db…
Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 29344    Accepted Submission(s): 7688 Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat…
传送门 Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat rings are pitched at some toys, with all the toys encircled awarded…
[题目链接] http://acm.hdu.edu.cn/showproblem.php?pid=1007 [算法] 答案为平面最近点对距离除以2 [代码] #include <algorithm> #include <bitset> #include <cctype> #include <cerrno> #include <clocale> #include <cmath> #include <complex> #inc…
Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 47104    Accepted Submission(s): 12318 Problem Description Have you ever played quoit in a playground? Quoit is a game in which fla…
Problem UVA10054-The Necklace Time Limit: 3000 mSec Problem Description Input The input contains T test cases. The first line of the input contains the integer T. The first line of each test case contains an integer N (5 ≤ N ≤ 1000) giving the number o…