Problem Description The company "21st Century Fruits" has specialized in creating new sorts of fruits by transferring genes from one fruit into the genome of another one. Most times this method doesn't work, but sometimes, in very rare cases, a…

题意: 给两个水果名,要求他们的LCS部分只输出1次,其他照常输出,但是必须保持原来的顺序! 思路: 求LCS是常规的,但是输出麻烦了,要先求LCS,再标记两串中的所有LCS字符,在遇到LCS字符时,先输串1的,再输串2的,然后输该字符,以保证每个LCS字符输出前,两串中该字符前面的字符全部已输出. //#pragma comment(linker,"/STACK:102400000,102400000") #include <iostream> #include <…

链接:HDU-1053:Advanced Fruits 题意:将两个字符串合成一个串,不改变原串的相对顺序,可将相同字母合成一个,求合成后最短的字符串. 题解:LCS有三种状态转移方式,将每个点的状态转移方式记录下来,再回溯. #include <bits/stdc++.h> using namespace std; ; const int INF = 0x3f3f3f3f; ; + ; char s[maxn], t[maxn]; int slen, tlen; int dp[maxn][m…

Advanced Fruits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1360    Accepted Submission(s): 672Special Judge Problem Description The company "21st Century Fruits" has specialized in cre…

Advanced Fruits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3340    Accepted Submission(s): 1714Special Judge Problem Description The company "21st Century Fruits" has specialized in cr…

Advanced Fruits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1426    Accepted Submission(s): 719Special Judge Problem Description   The company "21st Century Fruits" has specialized in c…

Advanced Fruits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3613    Accepted Submission(s): 1867 Special Judge Problem Description The company "21st Century Fruits" has specialized in…

http://acm.hdu.edu.cn/showproblem.php?pid=1503 题意: 给出两个串,现在要确定一个尽量短的串,使得该串的子串包含了题目所给的两个串. 思路: 这道题目就是要我们求LCS,记录好路径就好. #include<iostream> #include<algorithm> #include<cstring> #include<cstdio> #include<sstream> #include<vect…

Problem Description The company "21st Century Fruits" has specialized in creating new sorts of fruits by transferring genes from one fruit into the genome of another one. Most times this method doesn't work, but sometimes, in very rare cases, a…

题意:给定两个字符串,让你求一个最短的字符串,并且这个字符串包含给定的两个. 析:看到这个题,我知道是DP,但是,不会啊...完全没有思路么,我就是个DP渣渣,一直不会做DP. 最后还是参考了一下题解,主要是这样的,要想最短,就必须让两个字符串重复的最多,也就是LCS, 然后把剩下的不相同的字符再给补上,说起来容易,实现起来,难!反正对我来说是难. 然后根据LCS的原理,我们对这个两字符串,进行标记,什么意思呢,就是说,如果某个字符是公共字符, 等到输出时,我们只输出一次,而对于不是公共的,我们…