P2896 [USACO08FEB]一起吃饭Eating Together 显然的最长不升/降子序列,求出最长值,则答案为$n-$最长值(改掉剩下的). 复杂度$O(nlogn)$ (然鹅有神仙写了$O(n)$模拟) #include<iostream> #include<cstdio> #include<cstring> #include<cctype> #define re register using namespace std; void read(…

P2896 [USACO08FEB]一起吃饭Eating Together 题目描述 The cows are so very silly about their dinner partners. They have organized themselves into three groups (conveniently numbered 1, 2, and 3) that insist upon dining together. The trouble starts when they lin…

题目描述 The cows are so very silly about their dinner partners. They have organized themselves into three groups (conveniently numbered 1, 2, and 3) that insist upon dining together. The trouble starts when they line up at the barn to enter the feeding…

传送门 可以考虑DP 设 f [ i ] [ 1/2/3 ] [ 0/1 ] 表示当前考虑到第 i 头牛,打算让当前位置的编号变成 1/2/3,并且打算让整段序列上升/下降 0/1 然后就对每种情况慢慢考虑转移就行了 可以发现第一维可以直接优化掉,然后空间就是 O(1),时间就是 O(n) 太简单就不用注释了吧... #include<iostream> #include<cstdio> #include<algorithm> #include<cstring&g…

https://www.luogu.org/problem/show?pid=2896 题目描述 The cows are so very silly about their dinner partners. They have organized themselves into three groups (conveniently numbered 1, 2, and 3) that insist upon dining together. The trouble starts when th…

传送门 由于 Di 只有 3 种情况,那么就很简单了 f[i][j][0] 表示前 i 个,且第 i 个变成 j 的 递增序列最小修改次数 f[i][j][1] 表示前 i 个,且第 i 个变成 j 的 递减序列最小修改次数 状态转移看代码. ——代码 #include <cstdio> #include <iostream> ; << ); ][]; inline long long read() { , f = ; char ch = getchar(); ; )…

super:可以用来修饰属性  方法   构造器 当子类与父类中有同名的属性时,可以通过   super.此属性  显式的调用父类声明的属性 若想调用子类的同名的属性“this.此属性” 2.当子类重写父类的方法以后,在子类中若想再显式的调用父类的被重写的方法,就需要使用 super.方法 3.super修饰构造器:通过在子类中使用“super(形参列表)”来显示的调用父类中指定的构造器 >在构造器内部,super(形参列表) 必须声明在首行 >在构造器内部,this(形参列表)或super(…

1711: [Usaco2007 Open]Dining吃饭 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 902  Solved: 476[Submit][Status][Discuss] Description 农夫JOHN为牛们做了很好的食品,但是牛吃饭很挑食. 每一头牛只喜欢吃一些食品和饮料而别的一概不吃.虽然他不一定能把所有牛喂饱,他还是想让尽可能多的牛吃到他们喜欢的食品和饮料. 农夫JOHN做了F (1 <= F <= 100) 种食品…

Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 872  Solved: 459 Description 农夫JOHN为牛们做了很好的食品,但是牛吃饭很挑食. 每一头牛只喜欢吃一些食品和饮料而别的一概不吃.虽然他不一定能把所有牛喂饱,他还是想让尽可能多的牛吃到他们喜欢的食品和饮料. 农夫JOHN做了F (1 <= F <= 100) 种食品并准备了D (1 <= D <= 100) 种饮料. 他的N (1 <= N <= 10…

Holedox Eating Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3362    Accepted Submission(s): 1145 Problem Description Holedox is a small animal which can be considered as one point. It lives i…