[LeetCode]390. Elimination Game 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/elimination-game/description/ 题目描述: There is a list of sorted integers from 1 to n. Starting from left to right, remove the first number and every other numb…

正规解法直接跳到代码上面一点的部分就可以了.但我想记录下自己的思考和尝试过程,希望二刷能看到问题所在. 找规律的时候写了好多,虽然规律很简单. 只要随便写3以上的例子,就应该发现,相邻的2个最后结果是一样的,n=8和n=9的结果都是6,n=10和n=11的结果都是8.. 当时我的想法是,8 9消除2次之后就和4 5的消除情况一样,6 7和3 4一样,那既然需要用到前面的步骤,肯定是动态规划. 然而,不管是DP[I]来自DP[I-2]还是来自DP[I/2]都似乎不正确,我相信如果每一轮都是从左往右…

There is a list of sorted integers from 1 to n. Starting from left to right, remove the first number and every other number afterward until you reach the end of the list. Repeat the previous step again, but this time from right to left, remove the ri…

很开心,自己想出来的一道题 There is a list of sorted integers from 1 to n. Starting from left to right, remove the first number and every other number afterward until you reach the end of the list. Repeat the previous step again, but this time from right to left,…

详见:https://leetcode.com/problems/elimination-game/description/ C++: 方法一: class Solution { public: int lastRemaining(int n) { return help(n, true); } int help(int n, bool left2right) { if (n == 1) { return 1; } if (left2right) { return 2 * help(n / 2,…

题目如下: 解题思路:对于这种数字类型的题目,数字一般都会有内在的规律.不管怎么操作了多少次,本题的数组一直是一个等差数列.从[1 2 3 4 5 6 7 8 9] -> [2 4 6 8] -> [2 6] -> [6]这个序列中,我们可以得到公差分别是1,2,4.如果我们把n扩大一点,打印出其中每一步剩余的数组序列,我们很容易发现公差是pow(2,n)次方,发现了这个规律后,一切就水到渠成了.接下来,我们只要记录每一次操作后剩下序列的low,high以及序列的长度,直到最后序列只有一…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

# 390. Elimination Game There is a list of sorted integers from 1 to n. Starting from left to right, remove the first number and every other number afterward until you reach the end of the list. Repeat the previous step again, but this time from righ…

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