HDOJ-ACM1097(JAVA) A hard puzzle】的更多相关文章

这道题就是HDOJ的1061的变形: 1061 :求n的n次方的个位数 http://www.cnblogs.com/xiezie/p/5596779.html 1097 :求n的m次方的个位数 因此,就不在这里赘述了 以下是JAVA实现: import java.io.BufferedInputStream; import java.util.ArrayList; import java.util.Scanner; public class Main { public static void…
刚刚开始用Java,代码难免不够简洁. import java.math.BigDecimal; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner cin = new Scanner(System.in); while (cin.hasNext()) { BigDecimal a = cin.nextBigDecimal(); BigDecimal b =…
题目和1061非常相似,几乎可以复用. #include <stdio.h> ][]; int main() { int a, b; int i, j; ; i<; ++i) { buf[i][] = ; buf[i][] = i; ; j<; ++j) { buf[i][j] = buf[i][j-]*i%; ]) break; buf[i][]++; } } while (scanf("%d %d", &a, &b) != EOF) { i…
数学归纳法,得证只需求得使18+ka被64整除的a.且a不超过65. #include <stdio.h> int main() { int i, j, k; while (scanf("%d", &k) != EOF) { j = ; ; i<; i++) { +k*i) % == ) { j = ; break; } } if (j) printf("%d\n", i); else printf("no\n"); }…
一.需求:计算网页访问量前三名 import org.apache.spark.rdd.RDD import org.apache.spark.{SparkConf, SparkContext} /** * 需求:计算网页访问量前三名 * 用户:喜欢视频 直播 * 帮助企业做经营和决策 * * 看数据 */ object UrlCount { def main(args: Array[String]): Unit = { //1.加载数据 val conf:SparkConf = new Spa…
Problem Description Ignatius is poor at math,he falls across a puzzle problem,so he has no choice but to appeal to Eddy. this problem describes that:f(x)=5*x^13+13*x^5+k*a*x,input a nonegative integer k(k<10000),to find the minimal nonegative integer…
Problem Description lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and b,how to know the a^b.everybody objects to this BT problem,so lcy makes the problem easier than begin. this puzzle describes that: gave a and b,how to know…
直接构造矩阵,最上面一行加一排1.高速幂计算矩阵的m次方,统计第一行的和 CRB and Puzzle Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 133    Accepted Submission(s): 63 Problem Description CRB is now playing Jigsaw Puzzle. There…
one recursive approach to solve hdu 1016, list all permutations, solve N-Queens puzzle. reference: the video of stanford cs106b lecture 10 by Julie Zelenski https://www.youtube.com/watch?v=NdF1QDTRkck // hdu 1016, 795MS #include <cstdio> #include &l…
trie树.以puzzle做trie树内存不够,从puzzle中直接找串应该会TLE.其实可以将查询组成trie树,离线做.扫描puzzle时注意仅三个方向即可. /* 1857 */ #include <iostream> #include <string> #include <map> #include <queue> #include <set> #include <stack> #include <vector>…