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Running a taxi station is not all that simple. Apart from the obvious demand for a centralised coordination of the cabs in order to pick up the customers calling to get a cab as soon as possible,there is also a need to schedule all the taxi rides whi…

http://poj.org/problem?id=2060 Taxi Cab Scheme Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5459   Accepted: 2286 Description Running a taxi station is not all that simple. Apart from the obvious demand for a centralised coordination…

Taxi Cab Scheme Time Limit: 10000ms Memory Limit: 32768KB This problem will be judged on HDU. Original ID: 135064-bit integer IO format: %I64d      Java class name: Main   Running a taxi station is not all that simple. Apart from the obvious demand f…

Taxi Cab Scheme Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 5710   Accepted: 2393 Description Running a taxi station is not all that simple. Apart from the obvious demand for a centralised coordination of the cabs in order to pick up…

Taxi Cab Scheme Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 231    Accepted Submission(s): 142 Problem Description Running a taxi station is not all that simple. Apart from the obvious deman…

Taxi Cab Scheme 时间限制: 1 Sec  内存限制: 64 MB 题目描述 Running a taxi station is not all that simple. Apart from the obvious demand for a centralised coordination of the cabs in order to pick up the customers calling to get a cab as soon as possible,there is…

/** 题目:Taxi Cab Scheme UVALive - 3126 最小路径覆盖解法(必须是DAG,有向无环图) = 结点数-最大匹配 链接:https://vjudge.net/problem/UVALive-3126 题意:lv lrj训练指南P357 思路:最小路径覆盖(必须是DAG,有向无环图) = 结点数-最大匹配 最小路径覆盖:就是在图中找尽量少的路径,使得每个节点恰好在一条路径上(不同的路径不能有公共点),单独的结点也可以作为一条路径. 时间是一个天然的序,因此可以构图G如…

UVA 1201 - Taxi Cab Scheme 题目链接 题意:给定一些乘客.每一个乘客须要一个出租车,有一个起始时刻,起点,终点,行走路程为曼哈顿距离,每辆出租车必须在乘客一分钟之前到达.问最少须要几辆出租车 思路:假设一辆车载完一个乘客a,能去载乘客b,就连一条有向边,这样做完整个图形成一个DAG,然后要求的最少数量就是最小路径覆盖.利用二分图最大匹配去做,把每一个点拆成两点.假设有边就连边,做一次最大匹配.n - 最大匹配数就是答案 代码: #include <cstdio> #i…

题意: 出租车公司有M个订单. 订单格式:     hh:mm  a  b  c  d 含义:在hh:mm这个时刻客人将从(a,b)这个位置出发,他(她)要去(c,d)这个位置. 规定1:从(a,b)到(c,d)所花的时间为:abs(a-c)+abs(b-d). 规定2:一辆出租车如果要接单,必须在客人出发前1分钟(包括)以前接单. 问,最少派出多少辆出租车,可以完成所有任务. 思路: 把每一笔单看成一个点,如果完成第i个单后可以接到第j个单,则 i->j连上线. 则题为:求这个DAG图的最小路…