Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…
Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…
Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…
Given an undirected graph, return true if and only if it is bipartite. Example 1: Input: [[1,3], [0,2], [1,3], [0,2]] Output: true Explanation: The graph looks like this: 0----1 | | | | 3----2 We can divide the vertices into two groups: {0, 2} and {1…
[LeetCode]785. Is Graph Bipartite? 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/is-graph-bipartite/description/ 题目描述: Given an undirected graph, return true if and only if it is bipartite. Re…
Given a set of N people (numbered 1, 2, ..., N), we would like to split everyone into two groups of any size. Each person may dislike some other people, and they should not go into the same group. Formally, if dislikes[i] = [a, b], it means it is not…
Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…
原题链接在这里:https://leetcode.com/problems/is-graph-bipartite/ 题目: Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that eve…
Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…
大意:给定二分图, 求将边染色, 使得任意邻接边不同色且使用颜色种类数最少 最少颜色数即为最大度数, 要输出方案的话, 对于每一条边(u,v), 求出u,v能使用的最小的颜色$t0$,$t1$ 若t0=t1, 直接染就行不会有冲突, 否则就染为t0, 这样的话可能产生冲突, 就将冲突的边换成t1, 依次递归下去 由于二分图的性质, 最终一定可以找到一条边不冲突 #include <iostream> #include <algorithm> #include <cstdio&…
Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node label and each neigh…
https://oj.leetcode.com/problems/clone-graph/ 图的拷贝,就是给一个图,再弄出一个一模一样的来. /** * Definition for undirected graph. * struct UndirectedGraphNode { * int label; * vector<UndirectedGraphNode *> neighbors; * UndirectedGraphNode(int x) : label(x) {}; * }; */…
Given a reference of a node in a connected undirected graph, return a deep copy (clone) of the graph. Each node in the graph contains a val (int) and a list (List[Node]) of its neighbors. Example: Input: {"$id":"1","neighbors"…
原题地址:https://oj.leetcode.com/problems/clone-graph/ 题意:实现对一个图的深拷贝. 解题思路:由于遍历一个图有两种方式:bfs和dfs.所以深拷贝一个图也可以采用这两种方法.不管使用dfs还是bfs都需要一个哈希表map来存储原图中的节点和新图中的节点的一一映射.map的作用在于替代bfs和dfs中的visit数组,一旦map中出现了映射关系,就说明已经复制完成,也就是已经访问过了. dfs代码: # Definition for a undire…
Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…
[抄题]: Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node…
Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to check whether these edges make up a valid tree. For example: Given n = 5 and edges = [[0, 1], [0, 2], [0, 3], [1, 4]], return tru…
Given an undirected graph, return true if and only if it is bipartite. Recall that a graph is bipartite if we can split it's set of nodes into two independent subsets A and B such that every edge in the graph has one node in A and another node in B.…
E. Graph Coloring 链接 n个点m条边的无向图,不保证联通,给每个点标号1,2,3.1号点个数n1,2号点个数n2,3号点个数n3.且每条边的两点,标号之差绝对值为1.如果有合法方案,需输出方案. 考虑每个联通子图,2只可以和1或者3连边,1只能和2连边,3只能和2连边,那么将1,3归为一堆,2归为一堆.每一堆内不存在边,构成一个独立点集,那么很明显是一个二分图,每次DFS可以找到二分图两部点的个数,如果存在奇环那么直接输出NO 对于每个联通子图,一个二分图,假设左部有 x 个点…
题目如下:实现克隆图的算法  题目链接 Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node…
C. Graph and String 题目连接: http://codeforces.com/contest/624/problem/C Description One day student Vasya was sitting on a lecture and mentioned a string s1s2... sn, consisting of letters "a", "b" and "c" that was written on hi…
Problem: Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to check whether these edges make up a valid tree. For example: Given n = 5 and edges = [[0, 1], [0, 2], [0, 3], [1, 4]], r…
某人在玩一个非常神奇的游戏.这个游戏中有一个左右各 nnn 个点的二分图,图中的边会按照一定的规律随机出现. 为了描述这些规律,某人将这些边分到若干个组中.每条边或者不属于任何组 (这样的边一定不会出现),或者只属于一个组. 有且仅有以下三类边的分组: 这类组每组只有一条边,该条边恰好有 50%50\%50% 的概率出现. 这类组每组恰好有两条边,这两条边有 50%50\%50% 的概率同时出现,有 50%50\%50% 的概率同时不出现. 这类组每组恰好有两条边,这两条边恰好出现一条,各有 5…
题意 题目链接 Sol 可以这样考虑,在原图中没有边相连的点的值肯定是a / c 那么直接二分图染色即可 #include<bits/stdc++.h> #define LL long long using namespace std; const int MAXN = 1001, INF = 1e9 + 10; inline int read() { char c = getchar(); int x = 0, f = 1; while(c < '0' || c > '9') {…
Clone GraphClone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization:Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node label and…
Given n nodes labeled from 0 to n-1 and a list of undirected edges (each edge is a pair of nodes), write a function to check whether these edges make up a valid tree. Example 1: Input: n = 5, and edges = [[0,1], [0,2], [0,3], [1,4]] Output: true Exam…
题目:https://www.lydsy.com/JudgeOnline/problem.php?id=5006 https://www.luogu.org/problemnew/show/P4547 算一种可行方案,只要确定出 n 条边即可:概率就是这 n 条边存在的概率,其他边视作无要求,概率贡献都是1:这样的话,一种方案对答案的贡献就是其概率. 考虑把第二组边和第三组边分成概率分别为 1/2 的两条独立的边.对于第二组边再加一条能把4个点都连起来的 1/4 的边,对于第三组边再加一条能把4…
克隆图记住:一个map一个queue,照葫芦画瓢BFS 找到一个节点就画一个对应的新的,用map对应,然后添加邻居,记录邻居到queue public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) { if (node==null) return node; UndirectedGraphNode res = new UndirectedGraphNode(node.label); Queue<UndirectedGraphNo…
[133]Clone Graph (2019年3月9日,复习) 给定一个图,返回它的深拷贝. 题解:dfs 或者 bfs 都可以 /* // Definition for a Node. class Node { public: int val; vector<Node*> neighbors; Node() {} Node(int _val, vector<Node*> _neighbors) { val = _val; neighbors = _neighbors; } };…
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