1046. Shortest Distance (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exit…

1046 Shortest Distance (20 分) The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits. Input Specification: Each input file contains one test case. For…

1046 Shortest Distance (20 分)   The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits. Input Specification: Each input file contains one test case. F…

PAT (Advanced Level) Practice 1046 Shortest Distance (20 分) 凌宸1642 题目描述: The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits. 译:你的任务很简单:给定 N 个出口,形成…

The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits. Input Specification: Each input file contains one test case. For each case, the first line con…

The task is really simple: given N exits on a highway which forms a simple cycle, you are supposed to tell the shortest distance between any pair of exits. Input Specification: Each input file contains one test case. For each case, the first line con…

#include<stdio.h> int main() { int n,m,a,b,tem,pre,p; int i,j; ]; while(scanf("%d",&n)!=EOF) { ans[]=; ;i<=n;i++) { scanf("%d",&tem); ans[i]=ans[i-]+tem; } getchar(); scanf("%d",&m); ;i<m;i++) { getcha…

处理一下前缀和. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<string> #include<vector> using namespace std; +; int a[maxn],n,…

一开始以为是最短路,结果是给你一个环,让你求环上两点之间的距离...那还做毛线 然而还是得做毛线 #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #define INF 0x3f3f3f3f using namespace std; +; int clockwise[maxn]; int main() { int n; int dis[maxn];…

题意: 输入一个正整数N(<=1e5),代表出口的数量,接下来输入N个正整数表示当前出口到下一个出口的距离.接着输入一个正整数M(<=10000),代表询问的次数,每次询问输入两个出口的序号,输出他们之间的最小距离. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ],sum[]; int main(){ ios::sync_with_stdio…