A. Little Elephant and Function time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The Little Elephant enjoys recursive functions. This time he enjoys the sorting function. Let a is a permuta…
E. Little Elephant and Shifts time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The Little Elephant has two permutations a and b of length n, consisting of numbers from 1 to n, inclusive. Le…
D. Little Elephant and Array time limit per test 4 seconds memory limit per test 256 megabytes input standard input output standard output The Little Elephant loves playing with arrays. He has array a, consisting of n positive integers, indexed from…
C. Little Elephant and Problem time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The Little Elephant has got a problem — somebody has been touching his sorted by non-decreasing array a of le…
B. Little Elephant and Numbers time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output The Little Elephant loves numbers. He has a positive integer x. The Little Elephant wants to find the number…
A - Little Elephant and Function 思路: 水题: 代码: #include <cstdio> #include <iostream> using namespace std; int n; int main() { scanf("%d",&n); printf("%d ",n); ;i<n;i++) printf("%d ",i); ; }…
D. Iterated Linear Function 题目连接: http://www.codeforces.com/contest/678/problem/D Description Consider a linear function f(x) = Ax + B. Let's define g(0)(x) = x and g(n)(x) = f(g(n - 1)(x)) for n > 0. For the given integer values A, B, n and x find t…
题目链接:http://codeforces.com/problemset/problem/678/D 简单的矩阵快速幂模版题 矩阵是这样的: #include <bits/stdc++.h> using namespace std; typedef __int64 LL; struct data { LL mat[][]; }; LL mod = 1e9 + ; data operator *(data a , data b) { data res; ; i <= ; ++i) { ;…
D. Iterated Linear Function time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Consider a linear function f(x) = Ax + B. Let's define g(0)(x) = x and g(n)(x) = f(g(n - 1)(x)) for n > 0. For…
D. Iterated Linear Function time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Consider a linear function f(x) = Ax + B. Let's define g(0)(x) = x and g(n)(x) = f(g(n - 1)(x))for n > 0. For the…
数论题还是好恶心啊. 题目大意:给你两个不超过1e12的数 x,y,定义一个f ( x, y ) 如果y==0 返回 0 否则返回1+ f ( x , y - gcd( x , y ) ); 思路:我们设gcd ( x , y) 为G,那么 设 x = A*G,y = B*G,我们考虑减去多少个G时x y 的gcd会改变,我们设减去 k个G的时候 x和y 的gcd为改变,即 A*G 和 ( B - k ) * G 的 gcd 改变了,什么情况下会改变呢,就是A 和( B - k )的gcd…
A. Little Elephant and Function 逆推. B. Little Elephant and Numbers \(O(\sqrt n)\)枚举约数. C. Little Elephant and Problem 排序后对应不相等的位置为2,且两数交换. D. Little Elephant and Array 离线+分块. E. Little Elephant and Shifts 每个数单独考虑. 假设\(x\)在数组\(a\)的位置\(i\),在数组\(b\)的位置\…
关于迭代器的内容, 另一点点,只是已经无关紧要了.应该算是一种扩展吧.就一起来开开眼界好了~ 笨木头花心贡献.哈?花心?不.是用心~ 转载请注明,原文地址: http://www.benmutou.com/archives/1721 文章来源:笨木头与游戏开发 1.避免创建闭合函数 我们之前一直在说的迭代器.都是要创建闭合函数.但,大家有没有想过,有了恒定状态和控制变量之后.是不是就不须要闭合函数了? 先来回想一下之前的迭代器函数: function dieDaiQi(t) local i =…
http://codeforces.com/contest/678/problem/D D. Iterated Linear Function Consider a linear function f(x) = Ax + B. Let's define g(0)(x) = x and g(n)(x) = f(g(n - 1)(x)) for n > 0. For the given integer values A, B, nand x find the value of g(n)(x) mod…
Little Elephant and Chess Time Limit:2000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u Submit Status Practice CodeForces 259A Description The Little Elephant loves chess very much. One day the Little Elephant and his friend decided…
A. Elephant 题目连接: http://www.codeforces.com/contest/617/problem/A Descriptionww.co An elephant decided to visit his friend. It turned out that the elephant's house is located at point 0 and his friend's house is located at point x(x > 0) of the coord…
M. Heaviside Function Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100187/problem/M Description Heaviside function is defined as the piecewise constant function whose value is zero for negative argument and one for non-negat…
C. Little Elephant and Shifts Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/problemset/problem/220/C Description The Little Elephant has two permutations a and b of length n, consisting of numbers from 1 to n, inclusive. Let's de…
