LeetCode-Palindrome Partitioning II[dp]】的更多相关文章

Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab",Return 1 since the palindrome partitioning ["aa",…
Palindrome Partitioning II Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab",Return 1 since the palindrome pa…
Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab", Return 1 since the palindrome partitioning ["aa"…
原题地址:https://oj.leetcode.com/problems/palindrome-partitioning-ii/ 题意: Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = …
参考:http://www.cppblog.com/wicbnu/archive/2013/03/18/198565.html 我太喜欢用dfs和回溯法了,但是这些暴力的方法加上剪枝之后复杂度依然是很高,显然不能达到题目的要求. 这个时候应该考虑动态规划,并且要复杂度尽量接近O(n^2)的算法. 下面这个方法更加简洁:自长到短找到回文串后,往后dfs,并记录递归深度表示并更新最小划分数.http://fisherlei.blogspot.com/2013/03/leetcode-palindro…
LeetCode:Palindrome Partitioning 题目如下:(把一个字符串划分成几个回文子串,枚举所有可能的划分) Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ […
Palindrome Partitioning II Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab",Return 1 since the palindrome pa…
https://leetcode.com/problems/palindrome-partitioning/ Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa&qu…
131. Palindrome Partitioning substr使用的是坐标值,不使用.begin()..end()这种迭代器 使用dfs,类似于subsets的题,每次判断要不要加入这个数 start每次是起始的位置,判断当前位置到起始位置是不是回文 class Solution { public: vector<vector<string>> partition(string s) { vector<vector<string> > result;…
Palindrome Partitioning II  Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab",Return 1 since the palindrome p…