一.题目 Chinese people think of '8' as the lucky digit. Bob also likes digit '8'. Moreover, Bob has his own lucky number L. Now he wants to construct his luckiest number which is the minimum among all positive integers that are a multiple of L and consi…
Alexandra and A*B Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 802    Accepted Submission(s): 211 Problem Description Alexandra has a little brother. He is new to programming. One day…
一,取模a%b 1,如果a>b,例如10%7=3,这是什么原因呢?可以根据下面的理解 10 =7*1+3,则模就是3 2,如果a<b,例如7%10 = 7,这时怎么得到的呢?根据下面来理解 7=10*0+7,则模就是7…
昨天终于把欧拉定理的证明看明白了...于是兴冲冲地写了2道题,发现自己啥都不会qwq 题意:给定一个正整数L<=2E+9,求至少多少个8连在一起组成正整数是L的倍数. 这很有意思么... 首先,连续的8可表示为:8*(10^x-1)/9; 那么就是L|8*(10^x-1)*9 => 9*L|8*(10^x-1) ,求最小的x: 我们设d=gcd(L,8) 则9*L/d | 8/d*(10^x-1),因为此时9*L/d 和 8/d 互质,所以9*L/d | 10^x-1,所以 10^x ≡ 1…
详见PoPoQQQ的博客.. #include <iostream> #include <cstring> #include <cstdio> #include <algorithm> #define LL long long using namespace std; LL KASE,p; inline LL Get_Phi(LL x) { LL Ret=x; ;i*i<=x;i++) ) { Ret/=i;Ret*=(i-); ) x/=i; } )…
The Luckiest Number 题目大意:给你一个int范围内的正整数n,求这样的最小的x,使得:连续的x个8可以被n整除. 注释:如果无解输出0.poj多组数据,第i组数据前面加上Case i: 即可. 想法:这题还是挺好的.我最开始的想法是一定有超级多的数输出0.然后...我就在哪里找啊找....其实这道题是一道比较好玩儿的数论题.我们思考:连续的8可用什么来表示出来?$\frac{(10^x-1)}{9}\cdot 8$.其实想到这一步这题就做完了.这题的精髓就在于告诉我们连续的连…
Chinese people think of '8' as the lucky digit. Bob also likes digit '8'. Moreover, Bob has his own lucky number L. Now he wants to construct his luckiest number which is the minimum among all positive integers that are a multiple of L and consist of…
The Luckiest number Time Limit: 1000ms Memory Limit: 32768KB This problem will be judged on HDU. Original ID: 246264-bit integer IO format: %I64d      Java class name: Main Chinese people think of '8' as the lucky digit. Bob also likes digit '8'. Mor…
The Luckiest number Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1163    Accepted Submission(s): 363 Problem Description Chinese people think of '8' as the lucky digit. Bob also likes digit '…
Big Number 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1212 ——每天在线,欢迎留言谈论. 题目大意: 给你两个数 n1,n2.其中n1 很大很大,n1%n2的值. 知识点: ①秦九韶公式:例:1314= ((1*10+3)*10+1)*10+4 ②(a*b)%c == (a%c)*(b%c) .(a+b)%c == (a%c)+(b%c) . 思路: 每步取模即可. C++ AC代码: #include <iostream> #…