John Doe is a famous DJ and, therefore, has the problem of optimizing the placement of songs on his tapes. For a given tape and for each song on that tape John knows the length of the song and the frequency of playing that song. His problem is to rec…

题目链接:uva 1346 - Songs 题目大意:John Doe 是一个著名的DJ,现在他有n首播放个曲, 每首歌曲有识别符key,歌曲长度l,以及播放频率q.想在John Doe 想将磁带上的歌曲重新排列,方便播放,播放所有歌曲有一个复杂度的计算∑(1≤i≤n)q[i] * ( ∑(1≤j≤i)l[j] ), 然后给出S,请输出重新排列后的第S首歌的识别码. 解题思路:为了使得复杂度越小,很明显的曲目长度小的要放前面,播放频率小的要放后面,所以每首歌增加一个k = l / q,即k越小的…

In a list of songs, the i-th song has a duration of time[i] seconds. Return the number of pairs of songs for which their total duration in seconds is divisible by 60.  Formally, we want the number of indices i < j with (time[i] + time[j]) % 60 == 0.…

In a list of songs, the i-th song has a duration of time[i] seconds. Return the number of pairs of songs for which their total duration in seconds is divisible by 60.  Formally, we want the number of indices i < j with (time[i] + time[j]) % 60 == 0.…

In a list of songs, the i-th song has a duration of time[i] seconds. Return the number of pairs of songs for which their total duration in seconds is divisible by 60.  Formally, we want the number of indices i < j with (time[i] + time[j]) % 60 == 0.…

eslint常会出现这样的错误提示,控制台打印:Type of the default value for 'songs' prop must be a function 解决办法有两种如下: 1:写一个函数,return一个数组 2: ES6 箭头函数写法 就可以解决这个个问题…

题目如下: In a list of songs, the i-th song has a duration of time[i] seconds. Return the number of pairs of songs for which their total duration in seconds is divisible by 60.  Formally, we want the number of indices i < j with (time[i] + time[j]) % 60…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/pairs-of-songs-with-total-durations-divisible-by-60/ 题目描述 In a list of songs, the i-th song has a duration of time[i] seconds. Return the…

题目大意:n张唱片,每张都有长度和频率,要求题目中公式值最小.求一个排序,输出该排序下第m张CD的id. 思路:贪心,长度越长放越后面,频率越低放越后面,所以按len/p去排序即可. #include<cstdio>#include<cstring>#include<algorithm>#include<cmath>using namespace std;struct CD{ int id; double len; double p;} cd[100000]…

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