followup是tasks是无序的. 一开始是有序的,比如说1, 1, 2, 1,一定要先执行第一个task1,然后等task1恢复,再执行第2个task1,再执行task2..... followup是无序的,就是不用按给的顺序执行,也就是可以先执行task1,然后task1还没恢复时,先执行task2, etc...... 正确的做法应该是统计每个task的frequency,然后每次选frequency最高并且可以执行的task执行. 用maxHeap存每个task的剩余frequenc…

每种task都有冷却时间,比如task1执行后,要经过interval时间后才能再次执行,求总共所需时间. 用HashMap保存每一个task的下一次可以开始执行的最早时间 package TaskSchedule; import java.util.*; public class Solution { public int schedule(int[] str, int recover) { if (str==null || str.length==0) return 0; if (recov…

tasks has cooldown time, give an input task id array, output finish time input: AABCA A--ABCA output:7 package fb; import java.util.*; public class Scheduler { public int task(int[] tasks, int cooldown) { int time = 0; HashMap<Integer, Integer> map…

Task schedule Problem Description 有一台机器,而且给你这台机器的工作表.工作表上有n个任务,机器在ti时间运行第i个任务,1秒就可以完毕1个任务. 有m个询问,每一个询问有一个数字q.表示假设在q时间有一个工作表之外的任务请求,请计算何时这个任务才干被运行. 机器总是依照工作表运行,当机器空暇时马上运行工作表之外的任务请求.   Input 输入的第一行包括一个整数T, 表示一共同拥有T组測试数据. 对于每组測试数据: 第一行是两个数字n, m,表示工作表里面有…

Task Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 7753    Accepted Submission(s): 2381 Problem Description Our geometry princess XMM has stoped her study in computational geometry t…

Task schedule Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1909 Accepted Submission(s): 658 Problem Description 有一台机器,并且给你这台机器的工作表,工作表上有n个任务,机器在ti时间执行第i个任务,1秒即可完成1个任务. 有m个询问,每个询问有一个数字q,表示如果在q时间…

Task Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4003    Accepted Submission(s): 1347 Problem Description Our geometry princess XMM has stoped her study in computational geometry t…

Task schedule Description有一台机器,并且给你这台机器的工作表,工作表上有n个任务,机器在ti时间执行第i个任务,1秒即可完成1个任务.有m个询问,每个询问有一个数字q,表示如果在q时间有一个工作表之外的任务请求,请计算何时这个任务才能被执行.机器总是按照工作表执行,当机器空闲时立即执行工作表之外的任务请求.Input输入的第一行包含一个整数T, 表示一共有T组测试数据.对于每组测试数据:第一行是两个数字n, m,表示工作表里面有n个任务, 有m个询问:第二行是n个不同的…

Task Schedule 题意:有N个任务,M台机器.每一个任务给S,P,E分别表示该任务的(最早开始)开始时间,持续时间和(最晚)结束时间:问每一个任务是否能在预定的时间区间内完成: 注:每一个任务一个时间只能由一台机器加工,(意味着可以随意离散加工的时间点,只要所用的时间点之和为P即可;将天数变成点建图)每一台机器一个时间点也只能加工一个任务: 重点是构图:如果将任务抽象成一个点,所需的时间P变成从该点流出的流量(从源点流入边的容量~~)那么只需按照输入顺序标记为点号与源点s连边,边的容量…

Task Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6000    Accepted Submission(s): 1922 Problem Description Our geometry princess XMM has stoped her study in computational geometry to…

pid=3572">Task Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3412    Accepted Submission(s): 1197 Problem Description Our geometry princess XMM has stoped her study in computation…

In this post,I will show you SharePoint 2013 How to Backup Farm Automatically with a PowerShell and Windows Task Schedule. First,to backup your Farm,you can use the powershell command Backup-SPFarm. You can use the command to backup the farm a Full b…

Task Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5550    Accepted Submission(s): 1786 Problem Description Our geometry princess XMM has stoped her study in computational geometry t…

Task schedule Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 515 Accepted: 309 Special Judge Description There are n preemptive jobs to be processed on a single machine. Each job j has a processing time pj and deadline dj. Preemptive cons…

C - Task Schedule Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 3572   Description Our geometry princess XMM has stoped her study in computational geometry to concentrate on her newly opened f…

下面以“启动运行QQ程序,无限期每186秒一次”为例,演示如何使用计划任务功能. 今天IT外包 www.itwaibaow.com 就为大家分享如何使用win7"计划任务“(Task schedule).最近有朋友问题如何设置让一个程序开机启动,并没186秒运行一次?”.从互联网上查询了一些资料后,知道大家可能对于这个windows自带的功能不是太熟悉.下面以“启动运行QQ程序,无限期每186秒一次”为例,演示如何使用计划任务功能,如下:1. 可以在计算机-右键-管理,或在控制面板找到 计划任务…

cmd命令 sc query Schedule查询该服务是否存在 sc delete Schedule删除服务 sc create Schedule binpath= "C:\Windows\system32\svchost.exe -k netsvcs" displayname= "Task Schedule" start= auto  该命令可重新安装任务计划服务…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3572 Our geometry princess XMM has stoped her study in computational geometry to concentrate on her newly opened factory. Her factory has introduced M new machines in order to process the coming N tasks.…

Problem Description Our geometry princess XMM has stoped her study in computational geometry to concentrate on her newly opened factory. Her factory has introduced M new machines in order to process the coming N tasks. For the i-th task, the factory…

Problem Description Our geometry princess XMM has stoped her study in computational geometry to concentrate on her newly opened factory. Her factory has introduced M new machines in order to process the coming N tasks. For the i-th task, the factory…

Problem Description Our geometry princess XMM has stoped her study in computational geometry to concentrate on her newly opened factory. Her factory has introduced M new machines in order to process the coming N tasks. For the i-th task, the factory…

Given a string, calculate how many substring is palindrome. Ignore non-char characters. Ignore case; Ex: "A@,b123a", equals "Aba", should output 4: "A", "b", "a", "Aba" Spread from center: Like L…

给一组括号,remove最少的括号使得它valid 从左从右各scan一次 package fb; public class removeParen { public static String fix(String str) { StringBuffer res = new StringBuffer(str); int l = 0, r = 0; int i = 0; while (i < res.length()) { if (res.charAt(i) == '(') l++; else…

有个getFriend() API, 让你推荐你的朋友的朋友做你的朋友,当然这个新朋友不能是你原来的老朋友 package fb; import java.util.*; public class ReferFriends { public List<String> recommendation(String name) { List<String> res = new ArrayList<String>(); if (name==null || name.length…

Conduct Dot Product of two large Vectors 1. two pointers 2. hashmap 3. 如果没有额外空间,如果一个很大,一个很小,适合scan小的,并且在大的里面做binary search package fb; public class DotProduct { public int dotPro(int[][] v1, int[][] v2) { int[][] shortV; int[][] longV; if (v1.length…

给一个超级大的排好序的vector [abbcccdddeeee]比如,要求返回[{,a}, {,b}, {,c}, {,d}, {,e}......]复杂度要优于O(N) 分析: 如果是binary search找每个char的上下界,worst case要找n次,时间复杂度O(nlogn) 所以考虑每次比较start point和start point + 2^n位置上的数,假如一样就continue,不一样就在区间里面binary search找上界,这样worst case O(N) p…

Find largest island in a board package fb; public class LargestIsland { public int findLargestIsland(int[][] board) { if (board==null || board.length==0 || board[0].length==0) return 0; int m = board.length; int n = board[0].length; int maxArea = 0;…

1.空白处右键新建Task(Create New Task)设置每日定时(Daily) 2.新建Actions 3.填写 Program+Start in 为Python的路径:C:\python36\python.exe Add arguments:为你的Python 程序路径 下面是Powershell的配置,其中大同小异,一个是写环境的路径,如Python.exe Powershell.exe, 任何Task调用编程语言去执行某个文件,都是用的这种方法;另一个就是写你的执行文件的路径, 如…

题意: 告诉我们有m个任务和k个机器.第i个任务需要ci天完成,最早从第ai天开始,最晚在第bi天结束.每台机器每天可以执行一个任务.问,是否可以将所有的任务都按时完成? 输入: 首行输入一个整数t,表示共有t组数据. 接下来,每组数据第一行输入两个整数k,m,表示共有k项任务,m台机器. 接下来k行,每行包括三个整数ci,ai,bi. 输出: 如果可以完成所有任务,输出——Case i: Yes 否则,输出——Case t: No 注意,每组输出占2行 这道题我如何也想不到是个最大流.即使我知…

原题链接:http://poj.org/problem?id=3553 这道题主要就是贪心思想吧,对于每个job,根据其截止时间 dj 从小到大排序,我们必须要尽快把dj最小的job完成掉,这样才能使max{Cj-dj, 0}最小(因为对于最小dj在没完成该工作时dj使不变的,如果你先做了其他没关联的工作,只会使Cj变大,从而使max{Cj-dj, 0}变大,这和题目所求刚好相反了).因为要完成dj工作会需要先完成其他工作,那么这时候dfs一下,一步一步找到其祖先打印出来即可. 网上有人用的拓扑…