C题:一道简单的C题卡了半天,我太菜了 题意:给你一个n*2的矩阵,每个位置有一个数字,对应一种管道,要求通道可不可以从左上通到右下 由提议可以看出,1,2对应的是直管道,3,4,5,6对应弯管道,只有弯管道成对才可以换行,直管道只能换列 只需直管道的时候往右走,弯管的时候判断一下对应的下一行情况,同时弯管就换行,不是就输出“NO” #include <iostream> #include <cstring> #include <string> #include <…
Codeforces Round #590 (Div. 3) Editorial 题目链接 官方题解 不要因为走得太远,就忘记为什么出发! Problem A 题目大意:商店有n件商品,每件商品有不同的价格,找出一个最小的可能值price,使得price * n >= sum,sum指的是原来商品价格的总和. 知识点:模拟 思路:求出sum/n向上取整即可,有两种方法.一是使用ceil()函数,但注意ceil()返回的是向上取整后的浮点数,所以要进行强制类型转换:二是直接向下取整,然后用if语句…
A. Equalize Prices Again 题目链接:https://codeforces.com/contest/1234/problem/A 题意:给你 n 个数 , 你需要改变这些数使得这 n 个数的值相等 , 并且要求改变后所有数的和需大于等于原来的所有数字的和 , 然后输出满足题意且改变后最小的数值 分析: 签到题.记原来 n 个数的和为 sum , 先取这些数的平均值 ave , 然后每次判断 ave * n >= sum 是否成立成立则直接输出 , 不成立将 ave ++ #…
链接: https://codeforces.com/contest/1234/problem/E 题意: Let's define pi(n) as the following permutation: [i,1,2,-,i−1,i+1,-,n]. This means that the i-th permutation is almost identity (i.e. which maps every element to itself) permutation but the elemen…
链接: https://codeforces.com/contest/1234/problem/D 题意: You are given a string s consisting of lowercase Latin letters and q queries for this string. Recall that the substring s[l;r] of the string s is the string slsl+1-sr. For example, the substrings…
链接: https://codeforces.com/contest/1234/problem/C 题意: You are given a system of pipes. It consists of two rows, each row consists of n pipes. The top left pipe has the coordinates (1,1) and the bottom right - (2,n). There are six types of pipes: two…
链接: https://codeforces.com/contest/1234/problem/B2 题意: The only difference between easy and hard versions are constraints on n and k. You are messaging in one of the popular social networks via your smartphone. Your smartphone can show at most k most…
链接: https://codeforces.com/contest/1234/problem/A 题意: You are both a shop keeper and a shop assistant at a small nearby shop. You have n goods, the i-th good costs ai coins. You got tired of remembering the price of each product when customers ask fo…
https://codeforces.com/contest/1234/problem/A A. Equalize Prices Again #include<bits/stdc++.h> using namespace std; typedef long long ll; int main(){ int n,a; int t; cin>>t; ll sum = ,ans; while(t--){ cin>>n;sum = ; ;i < n;++i){ cin&g…
传送门 题意: 给出一个只含前\(20\)个字符的字符串,现在可以选择一段区间进行翻转,问区间中字符各不相同时,最长长度为多少. 思路: 首先,容易将题意转换为选择两个字符各不相同的区间,然后长度相加取最大: 注意到字符串中满足条件的区间长度不超过\(20*n\),那么处理出所有区间,现在任务即为找到两个区间,其字符各不想同,且长度和最大: 因为最多\(20\)个字符,将满足条件的区间转换为二进制数,任务转换为找到两个数\(a_i,a_j\)满足\(a_i\&a_j=0\)且二进制为\(1\)的…