此题本质上是:求一个数去掉后缀零后是否是回文串 因此,代码分为: >>> 读入 >>> 删除后缀0 >>> 判断回文 >>> 转为数组存储 >>> 依次比较开头和结尾是否相同(头指针后移,尾指针前移) >>> 输出结果 所以,我们有了: #include <?????.?> //杜绝抄袭! ??? main() //杜绝抄袭! { int n; //读入 scanf("%d&q…
E. Palindrome QueryTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/gym/100570/problem/E Description De Prezer loves palindrome strings. A string s1s2...sn is palindrome if and only if it is equal to its reverse. De Prezer also love…
A. Mike and palindrome time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Mike has a string s consisting of only lowercase English letters. He wants to change exactly one character from the s…
题目 B. Peculiar Movie Preferences time limit per test 2 seconds memory limit per test 512 megabytes input standard input output standard output Mihai plans to watch a movie. He only likes palindromic movies, so he wants to skip some (possibly zero) sc…
Quasi Binary time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A number is called quasibinary if its decimal representation contains only digits 0 or 1. For example, numbers 0, 1, 101, 11001…
B. Quasi Binary   time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A number is called quasibinary if its decimal representation contains only digits 0 or 1. For example, numbers 0, 1, 101,…
题目: Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example,"A man, a plan, a canal: Panama" is a palindrome."race a car" is not a palindrome. Note:Have you consider tha…
[链接] 我是链接,点我呀:) [题意] 题意 [题解] 计算出来每个字母出现的次数. 把字典序大的奇数出现次数的字母换成字典序小的奇数出现次数的字母贪心即可. 注意只有一个字母的情况 然后贪心地把字典序小的字母放在前面就好 [代码] #include <bits/stdc++.h> #define rep1(i,a,b) for (int i = a;i <= b;i++) #define rep2(i,a,b) for (int i = a;i >= b;i--) #defin…
题目 NEKO#ΦωΦ has just got a new maze game on her PC! The game's main puzzle is a maze, in the forms of a \(2×n\) rectangle grid. NEKO's task is to lead a Nekomimi girl from cell \((1,1)\) to the gate at \((2,n)\) and escape the maze. The girl can only…
1.题目描述 2.问题分析 使用两个下标,检测下标对应的字符是否相等,若不相等,则考察子串. 3.代码 bool validPalindrome(string s) { , j = s.size()-; i < j ;i++,j--){ ,j) || isp(s,i,j-); } return true; } bool isp(string s, int l, int r){ for( int i = l, j= r; i < j; i++,j--){ if( s[i] != s[j] ) r…