HDU 6242】的更多相关文章

Geometry Problem HDU - 6242 Alice is interesting in computation geometry problem recently. She found a interesting problem and solved it easily. Now she will give this problem to you : You are given NN distinct points (Xi,Yi)(Xi,Yi) on the two-dimens…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6242 思路:当 n == 1 时 任取一点 p 作为圆心即可. n >= 2 && n < 5 时 此时有可能出现所有点共线,所以取任意俩点间中点作为圆的圆心. n >= 5 保证了有解.所以不可能有所有点共线的情况,随机取三个点在正解圆上的概率是 1/8,还是蛮大的.... 外学了下随机算法的写法....时间种子 time(0)要强制转成int,不然会WA,不造为啥....…
Geometry Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1091    Accepted Submission(s): 208Special Judge Problem Description Alice is interesting in computation geometry problem recen…
Alice is interesting in computation geometry problem recently. She found a interesting problem and solved it easily. Now she will give this problem to you : You are given NN distinct points (Xi,Yi)(Xi,Yi) on the two-dimensional plane. Your task is to…
题意略. 思路:这个题的思路非常诡异.由于题目保证存在这样一个圆,那么每个点在这个圆上的概率是1/2,我任选3个点,这3个点都在这个圆上的概率是1 / 8. 不都在这个圆上的概率是7 / 8,在这样选取30次后,还没有找到这个圆的概率是0.018,根据这个条件我们可以暴力验证. 详见代码: #include<bits/stdc++.h> #define maxn 100005 #define eps 1e-6 using namespace std; struct Point{ double…
Geometry Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1722    Accepted Submission(s): 304Special Judge Problem Description Alice is interesting in computation geometry problem recen…
Saving HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7194    Accepted Submission(s): 3345 Problem Description 话说上回讲到海东集团面临内外交困,公司的元老也只剩下XHD夫妇二人了.显然,作为多年拼搏的商人,XHD不会坐以待毙的.  一天,当他正在苦思冥想解困良策的…
http://acm.hdu.edu.cn/showproblem.php?pid=3037 Lucas定理模板. 现在才写,noip滚粗前兆QAQ #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef long long ll; int jc[100003]; int p; int ipow(int x, int b) { ll t = 1, w = x;…
http://acm.hdu.edu.cn/showproblem.php?pid=4859 题目大意: 在一个矩形周围都是海,这个矩形中有陆地,深海和浅海.浅海是可以填成陆地的. 求最多有多少条方格线满足两侧分别是海洋和陆地 这道题很神 首先考虑一下,什么情况下能够对答案做出贡献 就是相邻的两块不一样的时候 这样我们可以建立最小割模型,可是都说是最小割了 无法求出最大的不相同的东西 所以我们考虑转化,用总的配对数目 - 最小的相同的对数 至于最小的相同的对数怎么算呢? 我们考虑这样的构造方法:…
Special equations Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4569 Description Let f(x) = a nx n +...+ a 1x +a 0, in which a i (0 <= i <= n) are all known integers. We call f(x) 0 (mod…