[LeetCode] Add Two Numbers 两个数字相加   You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked…

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers…

1.题目描述 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two…

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 ->…

2.5 You have two numbers represented by a linked list, where each node contains a single digit. The digits are stored in reverse order, such that the 1's digit is at the head of the list. Write a function that adds the two numbers and returns the sum…

You have two numbers represented by a linked list, where each node contains a single digit. The digits are stored in reverse order, such that the 1's digit is at the head of the list. Write a function that adds the two numbers and returns the sum as…

题目标签:Linked List 题目给了我们两个 数字的linked list,让我们把它们相加,返回一个新的linked list. 因为题目要求不能 reverse,可以把 两个list 的数字都 存入 两个stack.利用了stack的特性,就可以从后面把数字相加,具体看code. Java Solution: Runtime:  6 ms, faster than 51.06% Memory Usage: 45.4 MB, less than 64.71% 完成日期:07/08/201…

数字反过来这个没有什么麻烦,就是镜像的去算十进制加法就可以了,然后就是简单的链表. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* addTwoNumbers(ListNode* l1, ListN…

注意进位的处理和节点为null的处理 public ListNode addTwoNumbers(ListNode l1, ListNode l2) { int flag = 0; ListNode res = null; ListNode temp = null; //注意如果进位不是0的话还要添加一个节点 while (l1!=null||l2!=null||flag!=0) { int cur = flag; flag = 0; if (l1!=null) { cur+=l1.val; l…

You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers…