LintCode - Copy List with Random Pointer LintCode - Copy List with Random Pointer Web Link Description Code - C Tips Web Link http://www.lintcode.com/en/problem/copy-list-with-random-pointer/ Description A linked list is given such that each node con…

类同:剑指 Offer 题目汇总索引第26题 Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 说明:分三步, 1. 每个节点复制其本身并链接在后面. 2, 复制…

133. Clone Graph Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors. OJ's undirected graph serialization: Nodes are labeled uniquely. We use # as a separator for each node, and , as a separator for node lab…

Copy List with Random Pointer A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 题目意思: 深拷贝一个给定的带random指针的链表,这个random指针可能会指向其他任意一个节点或者是为nu…

题目: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 题解: 如果要copy一个带有random pointer的list,主要的问题就是有可能这个random指向的位置还没有被copy到,所以解决方法都是多次扫描li…

Copy List with Random Pointer 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/copy-list-with-random-pointer/description/ Description A linked list is given such that each node contains an additional random pointer which could point to any node in the…

题目: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 题解: Solution 1 () class Solution { public: RandomListNode *copyRandomList(RandomLi…

[题目描述] A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 给出一个链表,每个节点包含一个额外增加的随机指针可以指向链表中的任何节点或空的节点. 返回一个深拷贝的链表. [题目链接] www.lintcode.com/…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这道链表的深度拷贝题的难点就在于如何处理随机指针的问题,由于每一个节点都有一个随机指针,这个指针可以为空,也可以指向链表的任意一个节点,如果我们在每生成一个新节点给其随机指…

问题: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.   结点的定义如下: /** * Definition for singly-linked list with a random pointer. * class…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 随机链表的节点数据结构 struct RandomListNode { int label; RandomListNode *next, *random; RandomLi…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 思路: 做过,先复制一遍指针,再复制random位置,再拆分两个链表. #include <iostream> #include <vector> #incl…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. Solution: Uses map to recorde node mapping between old linked list and new linked list…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 分析: 这题的关键其实是如何copy random pointer,找到一个random pointer指向的node, time complexity is O(n).…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 和第133题差不多,都是图的复制,区别在于这道题的label有可能是相同的,所以导致了map的key有可能相同,所以需要处理. 两种方法差不多.第二种更简洁. 1.在复制n…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. /** * Definition for singly-linked list with a random pointer. * struct RandomListNode…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 剑指offer里面的一道题,具体思路看不懂请查阅剑指offer /** * Definition for singly-linked list with a random…

Total Accepted: 53943 Total Submissions: 209664 Difficulty: Hard A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.  (M) Clone Graph   o(…

题目地址: https://oj.leetcode.com/problems/copy-list-with-random-pointer/ 题目内容: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. /** * Defi…

题目: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 提示: 此题有两种方法,一种是按照原链表next的顺序依次创建节点,并处理好新链表的next指针,同时把原节点与新节点的对应关系保存到一个hash_map中,然后第…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 给定一个链表,每个节点包含一个额外增加的随机指针,该指针可以指向链表中的任何节点或空节点. 要求返回这个链表的深度拷贝. 1ms /** * Definition for…

［抄题］: 给出一个链表,每个节点包含一个额外增加的随机指针可以指向链表中的任何节点或空的节点. 返回一个深拷贝的链表. ［思维问题］: ［一句话思路］: 完完全全地复制,否则不好操作. 1->1`->2->2`->3->3`->4->4` 紧随其后地复制,再拆开 ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: newNode是每次新建的节点,不用往后移.head每次要移动2格,才能复制.…

题目: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 解题思路: 拷贝链表时,新节点的random指针不太好设置,因为是随机的,所以如果采用常规方法,必须每设置一个新节点的random指针时,必须到两链表中进行查找.…

原题地址:https://oj.leetcode.com/problems/copy-list-with-random-pointer/ 题意: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 解题思路:这题主要是需要深…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list.   struct RandomListNode { int label; RandomListNode *next, *random; RandomListNode(int…

问题: A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 结点的定义如下: /** * Definition for singly-linked list with a random pointer. * class Ra…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 解题思路: 本题要求新建一个链表,使其完全等于输入链表,相当于对输入链表深复制. 题目的难点在于,原链表中有random指针,指向原链表对应的结点.当新链表建立时,需要对新…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 分析: 我们知道如果是简单的copy List 的话,那么我们只需要从头到尾遍历下来,new出对应个数的Node,并把它们的连接关系设置好就可以了,但是这道题目中每个节点N…

给大家推荐一道leetcode上的面试题,这道题的详细解说在<剑指offer>的P149页有思路解说.假设你手头有这本书.建议翻阅. 题目链接 here A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. RandomLi…

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null. Return a deep copy of the list. 这题用map做其实比较简单,但是一开始没想明白越想越乱,最后看了下别人的实现,思路还是很清晰的,代码如下所示: /** * Definition for singly-li…