SwapTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3102 Accepted Submission(s): 1117Special Judge Problem DescriptionGiven an N*N matrix with each entry equal to 0 or 1. You can swap any two rows…

题目链接:https://vjudge.net/problem/HDU-2819 Swap Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4003    Accepted Submission(s): 1478Special Judge Problem Description Given an N*N matrix with each…

Swap Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5728    Accepted Submission(s): 2157Special Judge Problem Description Given an N*N matrix with each entry equal to 0 or 1. You can swap any t…

Swap Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3371    Accepted Submission(s): 1235 Special Judge Problem Description Given an N*N matrix with each entry equal to 0 or 1. You can swap any…

Swap Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4932    Accepted Submission(s): 1836Special Judge 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2819 Description: Given an N*N matrix with e…

题目大意: 给定一个元素的值只有1或者0的矩阵,每次可以交换两行(列),问有没有方案使得对角线上的值都是1.题目没有限制需要交换多少次,也没限制行交换或者列交换,也没限制是主对角线还是副对角线.虽然没限制,但是解法都是差不多的. 这是09年的多校题目,对一般人来说,不看解题报告是无法做出来的.我是那种看了解题报告也没做出来,然后看了好几遍才看懂的人. http://www.cnblogs.com/jzlikewei/archive/2012/07/09/2583608.html 解题思路: 对于…

分析:将行和列缩点,即行对应二分图的X部,列对应二分图的Y部,然后交点为连接该行和该列的一条边.匹配时每点都会把整行整列占了,因此就不会出现冲突了. 传送门:hdu1281 棋盘游戏 #include <cstdio> #include <cstring> #include <string> #include <cmath> #include <iostream> #include <algorithm> #include <q…

题目链接:https://cn.vjudge.net/problem/HDU-2819 Given an N*N matrix with each entry equal to 0 or 1. You can swap any two rows or any two columns. Can you find a way to make all the diagonal entries equal to 1? InputThere are several test cases in the in…

背景起因: 记起以前的另一次也是关于内存的调优分享下   有个系统平时运行非常稳定运行(没经历过大并发考验),然而在一次活动后,人数并发一上来后,系统开始卡. 我按经验开始调优,在每个关键步骤的加入如下代码耗时统计进行压测:   long startTime = System.currentTimeMillis();  callRpc();   //这里比如调用RPC伪代码,当然还在插入数据库,中间件地方都加入统计  long costTime = (System.currentTimeMill…

简介 LVM是 Logical Volume Manager(逻辑卷管理)的简写,它是Linux环境下对磁盘分区进行管理的一种机制,它由Heinz Mauelshagen在Linux 2.4内核上实现. 物理存储介质(PhysicalStorageMedia) 指系统的物理存储设备:磁盘,如:/dev/hda./dev/sda等,是存储系统最底层的存储单元. 物理卷(Physical Volume,PV) 指磁盘分区或从逻辑上与磁盘分区具有同样功能的设备(如RAID),是LVM的基本存储逻辑块,…