题目大意 给一个有n个点,m条边的无向连通图,求所有点两两之间的最短路.$(2<=n<=10^5;n-1<=m<=n+42)$ solution 我们注意到$m-n+1$很小.先任意求一棵生成树,然后将剩余$m-n+1$条边涉及的点建一棵虚树.分类讨论如下情况即可: (1)不属于虚树上任意一条边的点到所有点的贡献:单次操作$O(1)$(合并到虚树边上的点) (2)一个点到同一条边内其它点的最短路和(非关键点):单次操作$O(1)$ (3)一个在虚树上某条边的点(包括关键点)到其它边…

B. Hamming Distance Sum   Genos needs your help. He was asked to solve the following programming problem by Saitama: The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as , where si…

B. Hamming Distance Sum 题目连接: http://www.codeforces.com/contest/608/problem/A Description Genos needs your help. He was asked to solve the following programming problem by Saitama: The length of some string s is denoted |s|. The Hamming distance betw…

B. Hamming Distance Sum time limit per test: 2 seconds memory limit per test:256 megabytes input: standard input output: standard output Genos needs your help. He was asked to solve the following programming problem by Saitama: The length of some str…

前缀和思想 Genos needs your help. He was asked to solve the following programming problem by Saitama: The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as , where si is the i-th charact…

Genos needs your help. He was asked to solve the following programming problem by Saitama: The length of some string s is denoted |s|. The Hamming distance between two strings s and t of equal length is defined as , where si is the i-th character of…

题目: http://codeforces.com/contest/608/problem/B 字符串a和字符串b进行比较,以题目中的第一个样例为例,我刚开始的想法是拿01与00.01.11.11从左到右挨个比较,希望能找到一些规律,结果并没有... 其实,如果我们能从整个比较过程来看这个问题,整个过程就没有那么难.题目要求的东西,其实就是a字符串和b字符串子串每次比较的不同的个数的总和,当我们像上面那个思路,拿a字符串每次移动一位,和b进行比较的时候,从整个过程来看,就相当于a的每一个元素从前…

题目链接:http://codeforces.com/problemset/problem/608/B 题目意思:给出两个字符串 a 和 b,然后在b中找出跟 a 一样长度的连续子串,每一位进行求相减的绝对值然后相加(这个讲得有点绕),直接举个例子就很容易理解了. 假设a = 01,b = 00111, 符合条件的b的子串有:00, 01, 11, 11 然后: |01-00| = |0-0| + |1-0| = 1,  |01-01| = |0-0| + |1-1| = 0, |01-11|…

  B. Hamming Distance Sum   time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Genos needs your help. He was asked to solve the following programming problem by Saitama: The length of some st…

这是小川的第次更新,第篇原创 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第265题(顺位题号是1184).公交车有n个从0到n-1的车站,形成一个圆圈.我们知道所有相邻车站对之间的距离,其中distance[i]是车站i与车站(i + 1)%n之间的距离. 公交车沿两个方向运行,即顺时针和逆时针.返回给定起点和终点之间的最短距离. 输入:distance = [1,2,3,4], start = 0, destination = 1 输出:1 说明:0与1之间的距离为1或9,…

题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=1227 题意:一维坐标上有n个点,位置已知,选出k(k <= n)个点,使得所有n个点与选定的点中最近的点的距离总和最小,求出最小值. 思路: 将点i的距离记为为dis[i],从i到j选出一点使此段距离和最小,则此点坐标为dis[(i + j) / 2] cost[i][j]为从i到j选出一点距离和的最小值.则求cost[i][j]的代码如下: cost[i][j] = 0; for(int k =…

水 A - Saitama Destroys Hotel 简单的模拟,小贪心.其实只要求max (ans, t + f); #include <bits/stdc++.h> using namespace std; #define lson l, mid, o << 1 #define rson mid + 1, r, o << 1 | 1 typedef long long ll; const int N = 1e5 + 5; const int INF = 0x3f…

Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution. For example, given array S = {-1 2…

最开始仿真和精度测试,基于 matlab 完成的. Demo_MakeTable.m (生成 Hash 表) %======================================== %*********************************** %******* 设定参数: ***************** %******* l : hash表个数 ******** %******* k : 各表关键字个数 ******* %=======================…

Fast Food Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 662 Appoint description:  System Crawler  (2015-08-27) Description   The fastfood chain McBurger owns several restaurants along a highway. Rec…

题目链接:Fast Food 题意:一条直线上有n个饭店,问建造k个原料厂(仍旧在商店位置)得到的最小距离 分析:见代码 //一条直线上有n个饭店,问建造k个原料厂(仍旧在商店位置)得到的最小距离 //首先预处理从i到j的最小距离,可以知道选的点必为(i+j)/2,所以用dis[i][j]记录距离 //dp[i][j]表示前j个建造了i个原料厂的最小距离, //状态转移:dp[i][j]从min(dp[i-1][m])(i-1<=m<=j-1)转移过来,因为 //需要建厂的位置可选在i~j,故…

题目链接 题意 : 有n个饭店,要求建k个供应点,要求每个供应点一定要建造在某个饭店的位置上,然后饭店都到最近的供应点拿货,求出所有饭店到最近的供应点的最短距离. 思路 : 一开始没看出来是DP,后来想想就想通了.预处理,如果要在下标为 i 到 j 的饭店建一个供应点,那一定是在下标为(i+j)/2的位置建造的,状态转移方程:dp[i][j] = dp[i-1][k-1]+dis[k][j](i <= k <= j) ,dp[i][j]代表的是在前 j 个饭店中建了 i 个供应点的最小距离.方…

[热烈庆祝ZOJ回归] P1002:简单的DFS #include <cstdio> #include <cstring> #include <algorithm> ][]; int N; int input() { scanf("%d",&N); ;i<N;i++) scanf("%s",map[i]); return N; } ][]; ,sizeof(disable)); } int dfs(int cur)…

机器学习之K近邻算法(KNN) 标签: python 算法 KNN 机械学习 苛求真理的欲望让我想要了解算法的本质,于是我开始了机械学习的算法之旅 from numpy import * import operator from collections import Counter #KNN需要测试集,训练集,标签和k值 #测试集:你需要测试的数据 #训练集:给定的标准数据 #标签:每个标准数据的类别 #k值 :测试集和训练集相比较下前K个最相识的训练集的值 # 用KNN算法找出测试集的类别 #…

描述:状态方程p[i][j]=dp[i-1][k]+dist(k+1,j),由于没搞懂距离dist是怎么计算的,以为是num[j]-num[k+1],结果wa了一次,在状态转移的时候,采用一个数组sc记录一下节点的位置 #include <cstdio> #include <cstring> #define N 0x7fffffff; int num[210]; int dp[35][210]; int sc[35][210]; void show(int cur,int pos)…

Fast Food Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2173    Accepted Submission(s): 930 Problem Description The fastfood chain McBurger owns several restaurants along a highway. Recently,…

题意:在一条公路上,有n个酒店,要建造k个供给站(建造在酒店所在的位置),给出酒店的位置,求怎么样建造供给站才干使得每一个酒店都能得到服务且所要走的路程最短. 思路:在i到j酒店建立一个供给站,要使得路程和最短,要将供给站建立在中间.假设i到j为偶数时,能够建立在中间两个数当中一个地方,假设是奇数时,应该建立在(i + j) / 2的地方.我们能够预处理从i到j酒店的最短路程和dis[i][j].所以能够得到d[i][j]表示i个供给站为前j个酒店服务时的最短路程和.之后的输出能够在计算的时候增…

有两个序列a,b,大小都为n,序列元素的值任意整形数,无序:要求:通过交换a,b中的元素,使[序列a元素的和]与[序列b元素的和]之间的差最小. 1. 将两序列合并为一个序列,并排序,得到sourceList2. 拿出最大元素Big,次大的元素Small3. 在余下的序列S[:-2]进行平分,得到序列max,min4. 将Small加到max序列,将Big加大min序列,重新计算新序列和,和大的为max,小的为min. 如下,提供递归版本和迭代版本的解体思路: #!/usr/bin/env py…

题目链接 Problem Description The center coordinate of the circle C is O, the coordinate of O is (0,0) , and the radius is r.P and Q are two points not outside the circle, and PO = QO.You need to find a point D on the circle, which makes PD+QD minimum.Out…

A. Saitama Destroys Hotel time limit per test:1 second memory limit per test:256 megabytes input:standard input output:standard output Saitama accidentally destroyed a hotel again. To repay the hotel company, Genos has volunteered to operate an eleva…

B. Hamming Distance Sum time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output     Genos needs your help. He was asked to solve the following programming problem by Saitama: The length of some st…

http://acm.fzu.edu.cn/problem.php?pid=1005 Description The fastfood chain McBurger owns several restaurants along a highway. Recently, they have decided to build several depots along the highway, each one located at a restaurant and supplying several…

Fast Food My Tags (Edit) Source : Unknown Time limit : 3 sec Memory limit : 32 M Submitted : 3777, Accepted : 1147 The fastfood chain McBurger owns several restaurants along a highway. Recently, they have decided to build several depots along the hig…

10192 最长公共子序列 http://uva.onlinejudge.org/index.php?option=com_onlinejudge& Itemid=8&page=show_problem&category=114&problem=1133&mosmsg= Submission+received+with+ID+13297616 */ #include <cstdio> #include <string.h> #include&…

题意:在一条路上有 n 个站点,并给定了每个站点的坐标,然后想要在 k 个站点旁边分别各建一个补给站,求所有站点到最近的补给站的距离和的最小值. 是的,毫无疑问,显然是 DP 问题,但是这题怎么递推还是需要考虑的,我一开始是以 dp [ k ] [ i ] 表示设好第 k 个补给站并讨论到第 i 个站点时的最短路径,即第 k 个补给站不一定是设在第 i 个站点的,但是敲了一半我就发现这样做非常麻烦,因为首先我必须记录下每次 dp 时最后一个站点的位置,其次我还要对于每个考虑到的站点分析最后一个补…