Constructing Roads Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 13518    Accepted Submission(s): 5128 Problem Description There are N villages, which are numbered from 1 to N, and you should…

最小生成树模板(嗯……在kuangbin模板里面抄的……) 最小生成树(prim) /** Prim求MST * 耗费矩阵cost[][],标号从0开始,0~n-1 * 返回最小生成树的权值,返回-1表示原图不连通 */ const int INF = 0x3f3f3f3f; const int MAXN = 110; bool vis[MAXN]; int lowc[MAXN]; int map[MAXN][MAXN]; int Prim(int cost[][MAXN], int n) {…

题目链接:HDU 1102 Constructing Roads Constructing Roads Problem Description There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can connect to each other. We say two village A and B are conne…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1102 Constructing Roads Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 27178    Accepted Submission(s): 10340 Problem Description There are N vil…

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=1102 Constructing Roads Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 21947    Accepted Submission(s): 8448 Problem Description There are N villa…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1102 Constructing Roads Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 14172    Accepted Submission(s): 5402 Problem Description There are N villa…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1102 题意:这道题实际上和hdu 1242 Rescue 非常相似,改变了输入方式之后, 本题实际上更适合用Prim来做. 用Kruscal的话要做一些变化. /*Constructing Roads Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s)…

Constructing Roads Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5227    Accepted Submission(s): 1896 Problem Description There are N villages, which are numbered from 1 to N, and you should b…

Constructing Roads There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can connect to each other. We say two village A and B are connected, if and only if there is a road between A and B,…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1102 Problem Description There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can connect to each other. We say two village A and B are conne…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1102 分析:看到这题给出的都是矩阵形式,就知道了可以用Prim算法求MST. #include <iostream> using namespace std; #define typec int #define V 101 const typec inf=0x3f3f3f3f; int vis[V]; typec lowc[V],cost[V][V]; /*======================…

Problem Description There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can connect to each other. We say two village A and B are connected, if and only if there is a road between A and B…

怎么说呢 这题就是个模板题 但是 hud你妹夫啊说好的只有一组数据呢??? 嗯??? wa到家都不认识了好吗 #include <cstdio> #include <cstring> #include <queue> #include <vector> #include <algorithm> #define INF 0x3f3f3f3f using namespace std; typedef pair<int, int> pii;…

注意标号要减一才为下标,还有已建设的路长可置为0 题目 #define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #include<string.h> #include <malloc.h> #include<stdlib.h> #include<algorithm> #include<iostream> using namespace std; #define M 110 #define…

题目大意:输入一个整数n,表示村庄的数目.在接下来的n行中,每行有n列,表示村庄i到村庄 j 的距离.(下面会结合样例说明).接着,输入一个整数q,表示已经有q条路修好. 在接下来的q行中,会给出修好的路的起始村庄和结束村庄.. 输入样例说明如下: 解题思路:最小生成树(kruscal算法) 1)以前的题会直接给村庄编号以及村庄距离.而这道题,这是给出村庄的距离矩阵.村庄的编号信息蕴含在 矩阵中.这时候的读取方法为: for(i = 1 ; i <= n ; ++i){ for(j = i +…

求最小生成树.有一点点的变化,就是有的边已经给出来了.所以,最小生成树里面必须有这些边,kruskal和prim算法都能够,prim更简单一些.有一点须要注意,用克鲁斯卡尔算法的时候须要将已经存在的边预处理一下,并查集转化为同一个祖先.记得要找他们的祖先再转化.普里姆算法仅仅须要将那些已经存在的边都初始化为0就能够了. kruskal: #include<iostream> #include<cstdlib> #include<cstring> #include<…

Constructing Roads Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18256    Accepted Submission(s): 6970 Problem Description There are N villages, which are numbered from 1 to N, and you should…

杭电ACM分类: 1001 整数求和 水题1002 C语言实验题——两个数比较 水题1003 1.2.3.4.5... 简单题1004 渊子赛马 排序+贪心的方法归并1005 Hero In Maze 广度搜索1006 Redraiment猜想 数论:容斥定理1007 童年生活二三事 递推题1008 University 简单hash1009 目标柏林 简单模拟题1010 Rails 模拟题(堆栈)1011 Box of Bricks 简单题1012 IMMEDIATE DECODABILITY…

Constructing Roads Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1102 Description There are N villages, which are numbered from 1 to N, and you should build some roads such that every two vill…

Robberies 点击打开链接 背包;第一次做的时候把概率当做背包(放大100000倍化为整数):在此范围内最多能抢多少钱  最脑残的是把总的概率以为是抢N家银行的概率之和- 把状态转移方程写成了f[j]=max{f[j],f[j-q[i].v]+q[i].money}(f[j]表示在概率j之下能抢的大洋);  正确的方程是:f[j]=max(f[j],f[j-q[i].money]*q[i].v)  当中,f[j]表示抢j块大洋的最大的逃脱概率,条件是f[j-q[i].money]可达,也就…

杭电acm题目分类版本1 1002 简单的大数 1003 DP经典问题,最大连续子段和 1004 简单题 1005 找规律(循环点) 1006 感觉有点BT的题,我到现在还没过 1007 经典问题,最近点对问题,用分治 1008 简单题 1009 贪心 1010 搜索题,剪枝很关键 1011 1012 简单题 1013 简单题(有个小陷阱) 1014 简单题 1015 可以看作搜索题吧 1016 经典的搜索 1017 简单数学题 1018 简单数学题 1019 简单数学题 1020 简单的字符串…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1102 /************************************************************************/ /* hdu Constructing Roads 最小生成树 题目大意:在N个村子中已经存在部分存在连通,建最少长度的路使得所有的村子连通. 解题思路:已经连通的村子其中间的路径作为0,即修建的时候修建为0耗费,求这些节点的最小生成树. */ /*…

最近在尝试做acm试题,刚刚是1001题就把我困住了,这是题目: Problem Description In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.   Input The input will consist of a series of integers n, one integer per line   Output For each case, output SUM(n) in one…

F. Constructing Roads There are N villages, which are numbered from 1 to N, and you should build some roads such that every two villages can connect to each other. We say two village A and B are connected, if and only if there is a road between A and…

Constructing Roads Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10651    Accepted Submission(s): 3967 Problem Description There are N villages, which are numbered from 1 to N, and you should…

从杭电第一题开始A,发现做到1002就不会了,经过几天时间终于A出来了,顺便整理了一下关于大数的东西 其实这是刘汝佳老师在<算法竞赛 经典入门 第二版> 中所讲的模板,代码原封不动写上的,但是经过自己的使用与调试也明白了其中的内涵. 首先定义大数的结构体: struct BigNum{ ; ; vector<int> s; BigNum(){ *this=num; } BigNum operator = (long long num){ s.clear(); //vector.cl…

Constructing Roads In JGShining's Kingdom  HDU1025 题目主要理解要用LCS进行求解! 并且一般的求法会超时!!要用二分!!! 最后蛋疼的是输出格式的注意(直接报错误!!!) #include<iostream> #include<stdio.h> #include<algorithm> #include<string.h> using namespace std; ],dp[]; int main() { ,…

畅通工程 Problem Description 某省调查城镇交通状况,得到现有城镇道路统计表,表中列出了每条道路直接连通的城镇.省政府"畅通工程"的目标是使全省任何两个城镇间都可以实现交通(但不一定有直接的道路相连,只要互相间接通过道路可达即可).问最少还需要建设多少条道路?    Input 测试输入包含若干测试用例.每个测试用例的第1行给出两个正整数,分别是城镇数目N ( < 1000 )和道路数目M:随后的M行对应M条道路,每行给出一对正整数,分别是该条道路直接连通的两个…

Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 14635    Accepted Submission(s): 4158 Problem Description JGShining's kingdom consists of 2n(n is no mo…

Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 23467    Accepted Submission(s): 6710 Problem Description JGShining's kingdom consists of 2n(n is no mo…