Give a binary tree, elegantly print it so that no two tree nodes share the same column. Requirement: left child should appear on the left column of root, and right child should appear on the right of root. Example: a b c d e f z g h i j 这道题若能发现inorde…
Print a binary tree in an m*n 2D string array following these rules: The row number m should be equal to the height of the given binary tree. The column number n should always be an odd number. The root node's value (in string format) should be put i…
Print a binary tree in an m*n 2D string array following these rules: The row number m should be equal to the height of the given binary tree. The column number n should always be an odd number. The root node's value (in string format) should be put i…
Print a binary tree in an m*n 2D string array following these rules: The row number m should be equal to the height of the given binary tree. The column number n should always be an odd number. The root node's value (in string format) should be put i…
题目: Print a binary tree in an m*n 2D string array following these rules: The row number m should be equal to the height of the given binary tree. The column number n should always be an odd number. The root node's value (in string format) should be p…
Print a binary tree in an m*n 2D string array following these rules: The row number m should be equal to the height of the given binary tree. The column number n should always be an odd number. The root node's value (in string format) should be put i…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 DFS BFS 日期 题目地址:https://leetcode.com/problems/print-binary-tree/description/ 题目描述 Print a binary tree in an m*n 2D string array following these rules: The row number m should b…
https://leetcode.com/problems/print-binary-tree/ 打印整棵二叉树 class Solution { public: int getTreeHeight(TreeNode* root) { :max(getTreeHeight(root->left), getTreeHeight(root->right))+; } vector<vector<string>> printTree(TreeNode* root) { int…
https://www.geeksforgeeks.org/bfs-vs-dfs-binary-tree/ What are BFS and DFS for Binary Tree? A Tree is typically traversed in two ways: Breadth First Traversal (Or Level Order Traversal) Depth First Traversals Inorder Traversal (Left-Root-Right) Preor…
1.二叉搜索树:去一个陌生的城市问路到目的地: for each node, all elements in its left subtree are less-or-equal to the node (<=), and all the elements in its right subtree are greater than the node (>). 给予一个已经排序好的整数数组, 生成一个相对合理的二叉搜索树.(?相对合理的?) 给予一个二叉树的根节点,验证该树是否是二叉树搜索树,(…