The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

Read N Characters Given Read4 The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the rea…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

想了好一会才看懂题目意思,应该是: 这里指的可以调用更多次,是指对一个文件多次操作,也就是对于一个case进行多次的readn操作.上一题是只进行一次reandn,所以每次返回的是文件的长度或者是n,并且将相应的字符存在buf里.现在调用多次的话就可能存在以下的例子: 例如文件case是:1,2,3,4,5,6,7 如果要实现read5,先用read4读四个到buf,再用read4读剩下的3个到buf+4之后,但是read5一次最多读5个到buf,所以read4多读的2个就要存起来,防止下次调用…

原题链接在这里:https://leetcode.com/problems/read-n-characters-given-read4-ii-call-multiple-times/ 题目: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns…

题目: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the func…

The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file. By using the read4 API, implement the function…

Difficulty: Hard  More:[目录]LeetCode Java实现 Description Similar to Question [Read N Characters Given Read4], but the read function may be called multiple times. Intuition 题意:本题与上一题的区别就是连续多次调用read()函数,所以需要将存储4个字符的缓存buffer定义为全局变量,此外全局变量还需要定义buffer[]中的开始…

The API: int read4(char *buf) reads 4 characters at a time from a file.The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.By using the read4 API, implement the function i…