https://leetcode.com/problems/bitwise-and-of-numbers-range/discuss/56729/Bit-operation-solution(JAVA) 面试官,你再问我 Bit Operation 试试? 描述 Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusi…
Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 解题思路: 本题有很多思路,最简单的方法: result就是m和n二进制前面相同的部分!!! JAVA实现如下: public int ra…
Problem: Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. Analysis: The idea behind this problem is not hard, you could…
Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 题解:如果m==n,那么答案就是m. 如果m<n,那么二进制最右边一位在最后的结果中肯定是0,那么就可以转化成子问题: rangeBi…
https://leetcode.com/problems/bitwise-and-of-numbers-range/ [n,m]区间的合取总值就是n,m对齐后前面一段相同的数位的值 比如 5:101 7:111 结果就是 4:100 class Solution { public: int rangeBitwiseAnd(int m, int n) { int len = 0; long long tmp = 1; for(;tmp <= n || tmp <= m;len++){tmp&l…
[LeetCode]201. Bitwise AND of Numbers Range 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/bitwise-and-of-numbers-range/description/ 题目描述: Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers i…
Bitwise AND of Numbers Range Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. Example 1: Input: [5,7] Output: 4 Example 2: Input: [0,1] Output: 0 解法1 一个一个做位与,但是会超时... 解法2 事实: 与运…
Bitwise AND of Numbers Range Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. Credits:Special thanks to @amrsaqr for a…
Compare Version Numbers Compare two version numbers version1 and version2. If *version1* > *version2* return 1; if *version1* < *version2* return -1;otherwise return 0. You may assume that the version strings are non-empty and contain only digits an…
在Java位运算总结-leetcode题目博文中总结了Java提供的按位运算操作符,今天又碰到LeetCode中一道按位操作的题目 Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. 题意:…
