问题描述:寻找反转序列中最小的元素. 算法分析:和寻找某个数是一个道理,还是利用二分查找,总体上分两种情况.nums[left]<=nums[mid],else.但是,在截取子序列的时候,有可能得到一个顺序序列.如34512,截取后得到12,此时要对这种情况判断,因为是顺序的,所以,最左边的元素就是最小元素.这点区别于寻找target,因为寻找target是根据target和left,mid,right做比较判断的.所以就不用对这种顺序情况单独讨论了. public int findMin(in…
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 这道寻找旋转有序数组的最小值肯定不能通过直接遍历整个数组来寻找,这个方法过于简单粗暴,这样的话,旋不…
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. You may assume no duplicate exists in the array. Example 1: Input: [3,4,5…
题目: Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. You may assume no duplicate exists in the array. Example 1: Input: [3…
Add Date 2014-10-15 Find Minimum in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the…
问题描述:一个有序序列经过反转,得到一个新的序列,查找新序列的某个元素.12345->45123. 算法思想:利用二分查找的思想,都是把要找的目标元素限制在一个小范围的有序序列中.这个题和二分查找的区别是,序列经过mid拆分后,是一个非连续的序列.特别要注意target的上下限问题.因为是非连续,所以要考虑上下限,而二分查找,序列式连续的,只用考虑单限.有递归算法和迭代算法. 递归算法: public int search(int[] nums, int target) { return bin…
Given a sorted array, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. Ex…
一.题目 Description Given a sorted array, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) e…
