这是leetcode第一题,通过较为简单. 第一题用来测试的,用的c,直接暴力法过, /** * Note: The returned array must be malloced, assume caller calls free(). */ int* twoSum(int* nums, int numsSize, int target) { ]={}; ;i<numsSize-;i++) ;j<numsSize;j++) if(nums[i]+nums[j]==target){ a[]=i…

LeetCode 算法题解 js 版 (001 Two Sum) 两数之和 https://leetcode.com/problems/two-sum/submissions/ https://leetcode-cn.com/problems/two-sum/submissions/ 1. 暴力解法 Time complexity: O(n**2) Space complexity: O(n) "use strict"; /** * @author xgqfrms * @descrip…

博客搬至blog.csgrandeur.com,cnblogs不再更新. 新的题解会更新在新博客:http://blog.csgrandeur.com/2014/01/15/LeetCode-OJ-Solution/ ———————————————————————————————————————— ———————————————————————————————————————— LeetCode OJ 题解 LeetCode OJ is a platform for preparing tech…

LeetCode 2 Add Two Sum 解题报告 LeetCode第二题 Add Two Sum 首先我们看题目要求: You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return…

leetcode 练习1  two sum whowhoha@outlook.com 问题描述 Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution. Example: Given nums = [2, 7, 11,…

Given an array of n positive integers and a positive integer s, find the minimal length of a subarray of which the sum ≥ s. If there isn't one, return 0 instead. For example, given the array [2,3,1,2,4,3] and s = 7,the subarray [4,3] has the minimal…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum. For example: Given the below binary tree and sum = 22,…

一天一道LeetCode系列 (一)题目 Given a collection of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T. Each number in C may only be used once in the combination. Note: All numbers (including…

乘风破浪:LeetCode真题_040_Combination Sum II 一.前言 这次和上次的区别是元素不能重复使用了,这也简单,每一次去掉使用过的元素即可. 二.Combination Sum II 2.1 问题 2.2 分析与解决 通过分析我们可以知道使用递归就可以解决问题,并且这次我们从头遍历一次就不会出现多次使用某一个元素了. class Solution { List<List<Integer>> ans; public List<List<Intege…

乘风破浪:LeetCode真题_039_Combination Sum 一.前言     这一道题又是集合上面的问题,可以重复使用数字,来求得几个数之和等于目标. 二.Combination Sum 2.1 问题 2.2 分析与解决 我们可以先将大于该数字的元素去除掉,之后取出一个元素,做减法,将得到的结果再放到集合中比较,直至最后减得结果为零则成功,为负数则失败回退.因此我们可以使用递归.堆栈.队列等来解决. public class Solution { public List<List<…