牛奶模式 时间限制: 5000MS   内存限制: 65536K 提交总数: 16796   接受: 7422 案件时间限制: 2000MS 描述 农夫约翰已经注意到,他的牛奶的质量每天都在变化.经进一步调查,他发现虽然不能预测一天到下一天的牛奶质量,但每天的牛奶质量有一些规律. 要执行严格的研究,他已经发明了其中每个奶样本被记录为0到1,000,000之间的整数一个复杂的分类方案,并且已经从单一的母牛超过记录数据Ñ(1≤ Ñ ≤20000)天.他希望找到其等同至少K(2≤重复样品的最长图案ķ …

题意:求字符串的可重叠的k次最长重复子串 n<=20000 a[i]<=1000000 思路:后缀数组+二分答案x,根据height分组,每组之间的height>=x 因为可以重叠,所以只要判断是否有一组的height个数>=k即可 ..]of longint; n,m,i,l,r,mid,last,k1:longint; procedure swap(var x,y:longint); var t:longint; begin t:=x; x:=y; y:=t; end; fun…

Milk Patterns Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 7938   Accepted: 3598 Case Time Limit: 2000MS Description Farmer John has noticed that the quality of milk given by his cows varies from day to day. On further investigation,…

Milk Patterns Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 16742   Accepted: 7390 Case Time Limit: 2000MS Description Farmer John has noticed that the quality of milk given by his cows varies from day to day. On further investigation,…

题目题目:http://poj.org/problem?id=3261 Milk Patterns Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 18880 Accepted: 8336 Case Time Limit: 2000MS Description Farmer John has noticed that the quality of milk given by his cows varies from day t…

[题目链接] http://poj.org/problem?id=3261 [题目大意] 求最长可允许重叠的出现次数不小于k的子串. [题解] 对原串做一遍后缀数组,二分子串长度x,将前缀相同长度超过x的后缀分组, 如果存在一个大小不小于k的分组,则说明答案可行,分治得到最大可行解就是答案. [代码] #include <cstdio> #include <cstring> #include <vector> using namespace std; const int…

题意:给定一个字符串,求至少出现k 次的最长重复子串,这k 个子串可以重叠. 分析:经典的后缀数组求解题:先二分答案,然后将后缀分成若干组.这里要判断的是有没有一个组的符合要求的后缀个数(height[i] >= mid)不小于k.如果有,那么存在 k 个相同的子串满足条件,否则不存在. #include <cstdio> #include <iostream> #include <cstring> #include <algorithm> using…

Farmer John has noticed that the quality of milk given by his cows varies from day to day. On further investigation, he discovered that although he can't predict the quality of milk from one day to the next, there are some regular patterns in the dai…

题目大意:找出至少出现K次的子串的最长长度. 题目分析:二分枚举长度x,判断有没有最长公共前缀不小于x的并且连续出现了至少k次的有序子串区间. 代码如下: # include<iostream> # include<cstdio> # include<map> # include<vector> # include<cstring> # include<algorithm> using namespace std; # define…

[题目链接] http://poj.org/problem?id=3261 [题意] 至少出现k次的可重叠最长子串. [思路] 二分长度+划分height,然后判断是否存在一组的数目不小于k即可. 需要注意的是:用末尾添0的方法解决n==1时的RE问题,但是在can中需要忽略height[0]且考虑height[1..n]. [代码] #include<cstdio> #include<cstring> #include<iostream> #define FOR(a,…