今天做的沈阳站重现赛,自己还是太水,只做出两道签到题,另外两道看懂题意了,但是也没能做出来. 1. Thickest Burger Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 0    Accepted Submission(s): 0 Problem Description ACM ICPC is launching a thic…

C.Recursive sequence 求ans(x),ans(1)=a,ans(2)=b,ans(n)=ans(n-2)*2+ans(n-1)+n^4 如果直接就去解...很难,毕竟不是那种可以直接化成矩阵的格式,我们也因为这个被卡很长时间 事实上可以把这道式子化成几个基本元素的格式,然后就容易组合了,比如ans(n-2)*2+ans(n-1)+(n-1)^4+4*(n-1)^3+6*(n-1)^2+4*(n-1)^1+1 包含了所有的基本组成形式,化绝对为相对,并且除了一个n-2其他都是n…

Recursive sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 249    Accepted Submission(s): 140 Problem Description Farmer John likes to play mathematics games with his N cows. Recently, t…

Counting Cliques Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 539    Accepted Submission(s): 204 Problem Description A clique is a complete graph, in which there is an edge between every pair…

Thickest Burger Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 63    Accepted Submission(s): 60 Problem Description ACM ICPC is launching a thick burger. The thickness (or the height) of a piec…

Relative atomic mass Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 66    Accepted Submission(s): 59 Problem Description Relative atomic mass is a dimensionless physical quantity, the ratio of…

Rabbits Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1193    Accepted Submission(s): 628 Problem Description Here N (N ≥ 3) rabbits are playing by the river. They are playing on a number li…

整理代码... Little Boxes Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 2304    Accepted Submission(s): 818 Problem Description Little boxes on the hillside.Little boxes made of ticky-tacky.Littl…

题目链接:http://acm.hdu.edu.cn/search.php?field=problem&key=2016ACM%2FICPC%D1%C7%D6%DE%C7%F8%B4%F3%C1%AC%D5%BE-%D6%D8%CF%D6%C8%FC%A3%A8%B8%D0%D0%BB%B4%F3%C1%AC%BA%A3%CA%C2%B4%F3%D1%A7%A3%A9&source=1&searchmode=source A.染色乱搞. #include <bits/stdc…

1001题意:n个人,给m对敌对关系,X个好人,Y个坏人.现在问你是否每个人都是要么是好人,要么是坏人. 先看看与X,Y个人有联通的人是否有矛盾,没有矛盾的话咋就继续遍历那些不确定的人关系,随便取一个数3,与其相连的就是4,间隔就要相同,dfs搜过去就可以判断了 #include<bits/stdc++.h> using namespace std; #pragma comment(linker, "/STACK:102400000,102400000") #define…