Write a class StockSpanner which collects daily price quotes for some stock, and returns the span of that stock's price for the current day. The span of the stock's price today is defined as the maximum number of consecutive days (starting from today…

Write a class StockSpanner which collects daily price quotes for some stock, and returns the span of that stock's price for the current day. The span of the stock's price today is defined as the maximum number of consecutive days (starting from today…

Write a class StockSpanner which collects daily price quotes for some stock, and returns the span of that stock's price for the current day. The span of the stock's price today is defined as the maximum number of consecutive days (starting from today…

Write a class StockSpanner which collects daily price quotes for some stock, and returns the span of that stock's price for the current day. The span of the stock's price today is defined as the maximum number of consecutive days (starting from today…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 单调递减栈 日期 题目地址:https://leetcode.com/problems/online-stock-span/description/ 题目描述 Write a class StockSpanner which collects daily price quotes for some stock, and returns the spa…

题目如下: 解题思路:和[leetcode]84. Largest Rectangle in Histogram的核心是一样的,都是要找出当前元素之前第一个大于自己的元素. 代码如下: class StockSpanner(object): def __init__(self): self.cl = [] self.vl = [] def next(self, price): """ :type price: int :rtype: int """…

Span 指这个元素之前连续的小于这个元素的值有多少个 原理: 维护递减栈 这个栈内的元素是递减的序列 新到一个元素x 依次出栈比x小的(也就是这个元素的Span) 这种问题的关键在于 新来的元素如果比前一个元素小 那么答案是1 如果比前一个元素大 ( 那么前一个元素在之后就完全没有用了, 所以可以出栈, 使用现有的元素进行意义的记录 ) 相关题目 Unique Letter String Sum of Subsequence Widths 907 907是求一个双向的Span 但是有一个重复元…

Write a class StockSpanner which collects daily price quotes for some stock, and returns the span of that stock's price for the current day. The span of the stock's price today is defined as the maximum number of consecutive days (starting from today…

All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 把自己刷过的所有题目做一个整理,并且用简洁的语言概括了一下思路,汇总成了一个表格. 题目的排列顺序是按照先Easy再Medium再Hard排列的,暂时还没有把题目全部整理完成.后序我会把刷过的所有的题目都整理到这个文档里. 题目 难度 解法 题目地址 566. Reshape the Matrix Easy 变长数组,求余法,维护行列计算在新的数组中的位置 https://blog.c…

堆栈基础 堆栈(stack)具有“后进先出”的特性,利用这个特性我们可以用堆栈来解决这样一类问题:后续的输入会影响到前面的阶段性结果.线性地遍历输入并用stack处理,这类问题较简单,求解时间复杂度一般为O(n). 相关LeetCode题: 13. Roman to Integer  题解 20. Valid Parentheses  题解 844. Backspace String Compare  题解 1047. Remove All Adjacent Duplicates In Stri…

2018-11-16 22:45:48 一.单调队列 Monotone Queue 239. Sliding Window Maximum 问题描述: 问题求解: 本题是一个经典的可以使用双端队列或者说单调队列完成的题目,具体来说,就是通过双端队列将可能的最大值维护起来. public int[] maxSlidingWindow(int[] nums, int k) { if (nums == null || nums.length < k || k == 0) return new int[…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

Step  1app\design\frontend\base\default\template\catalog\product\list.phtml<?php    $_productCollection=$this->getLoadedProductCollection();    $_helper = $this->helper('catalog/output');?><?php if(!$_productCollection->count()): ?>&l…

什么是vuex? 官方的解释是:Vuex 是一个专为 Vue.js 应用程序开发的状态管理模式.它采用集中式存储管理应用的所有组件的状态,并以相应的规则保证状态以一种可预测的方式发生变化. 简单来说就是集中管理所有的状态. 为什么要用vuex? 对于父子组件之前的通信,父组件通过porps传递到子组件,子组件通过$emit发送事件都到父组件; 对于组件与组件之间的通信,可以new一个新的Vue实例,专门用来做event bus进行通信. 当多个组件之间共享一个状态时,event bus可能就变成…

上拉加载以及下拉刷新都是移动端很常见的功能,在搜索或者一些分类列表页面常常会用到. 跟横向滚动一样,我们还是采用better-scroll这个库来实现.由于better已经更新了新的版本,之前是0.几的版本,更新了一下发现,现在已经是1.2.6这个版本了,新版本多了些 比较好用的api,所以我也重写了之前的代码,用新的api来实现上拉加载以及下拉刷新. 首先把基本的样式写好,这里就略过了,然后引入better-scroll库 import BScroll from 'better-scroll'…

1. 开始前的准备 IDE:VSCode(推荐)或者Sublime Text 前导技术:JavaScript中级 2. 官方提供的product例程 product.html页面代码: <div id="app"> <ul> <li v-for="product in products"> <input type="number" v-model.number="product.quantity…

vue 颠覆式的开发方式 解疑 为什么要学习vue? 降低项目的复杂度 就业需要 vue难不难? 特别简单 相比于React,vue有什么优势? 前端三大框架:Angular.React.Vue Vue的优势: 1) 学习成本低 2) Vue已经自动对执行效率进行了优化,初学者完全不用考虑效率问题 vue的特点 渐进式:vue的侵入性很少,可以与很多其他前端技术联用 组件化 响应式:数据响应式,vue会监控数据的变化,当数据发生变化时,自动重新渲染页面 vue的核心功能 关于创建vue工程 直接…

<span style="font-family: Arial, Helvetica, sans-serif; background-color: rgb(255, 255, 255);">leetcode第188题,Best Time to Buy and Sell Stock IV题目如下:</span> https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iv/ Say you hav…

Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times) wit…

Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most k transactions. Note:You may not engage in multiple transactions at the same time (ie, yo…

Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note:You may not engage in multiple transactions at the same time (ie,…

Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). Ho…

Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. 这道题相…

问题: Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. 依旧还是那个熟悉的味道,如果II是I的另一个版本,那么III就是他们的一个升级版. 在这个版本中只能交易两次,也就是买卖各两次,其它条…

121. Best Time to Buy and Sell Stock Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algor…

原题链接在这里:https://leetcode.com/problems/best-time-to-buy-and-sell-stock-with-cooldown/ 题目: Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many…

Best Time to Buy and Sell Stock II Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one sha…

LeetCode:Best Time to Buy and Sell Stock Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an a…

Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most k transactions. 解题思路: https://leetcode.com/discuss/18330/is-it-best-solution-with-o-n-o-1…