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Problem We have a grid with R rows and C columns in which every entry is either 0 or 1. We are going to perform N operations on the grid, each of which is one of the following: Operation M: Change a number in one cell of the grid to 0 or 1 Operation…
For example we have array of meeting objects: const data = [ { name: }, { name: }, { name: }, { name: }, { name: } ]; For a day, 8 hours, we want to take as any meetings as possible: ); You should write function 'optimizeMeetings', get the results of…
题意:给定一个N个点的零图,M次操作,添加或删除一条边,每一次操作以后,打印用1,2,...N/2条边构成的匹配数. 分析:因为N的范围很小,所以可以把点的枚举状态用二进制表示集合.用一维数组dp[S]表示二进制集合为S的点集的匹配数. 每次加边操作,从大到小遍历集合,dp[S]+=dp[S-u-v]:删边操作,从小到大遍历集合,dp[S]-=dp[S-u-v]. 预处理出每个1024之内每个数对应二进制含有1的个数,每次记录答案就将每个dp[S]加到ans[S对应的二进制个数]中. #incl…
题意 大家都是优秀生,这点英文还是看得懂的:点此看题 题解 由于旅行路线成一个环,所以从哪里出发不重要,我们把景点按照 a i a_i ai​ 排序,不妨就从左边最小的出发.基础的旅行费用 c i c_i ci​ 是都要算上的,我们的目的是最小化额外的费用 ∑ max ⁡ ( 0 , ( a j − a i ) − c j ) \sum\max(0,(a_j-a_i)-c_j) ∑max(0,(aj​−ai​)−cj​) . 很明显有一部分的景点是回程(从大到小飞回起点)的时候经过的,这些景点一…
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