problem 938. Range Sum of BST 参考 1. Leetcode_easy_938. Range Sum of BST; 完…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 日期 题目地址:https://leetcode.com/contest/weekly-contest-110/problems/range-sum-of-bst/ 题目描述 Given the root node of a binary search tree, return the sum of values of all nodes wi…

Given the root node of a binary search tree, return the sum of values of all nodes with value between L and R (inclusive). The binary search tree is guaranteed to have unique values. Example 1: Input: root = [10,5,15,3,7,null,18], L = 7, R = 15 Outpu…

import functools # Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None @functools.lru_cache() class Solution(object): def rangeSumBST(self, root, L, R): ""&q…

https://leetcode-cn.com/problems/range-sum-of-bst/ 二叉树中序遍历 二叉搜索树性质:一个节点大于所有其左子树的节点,小于其所有右子树的节点 /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ clas…

771. Jewels and Stones (Easy)# You're given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are also…

这是悦乐书的第359次更新,第386篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第221题(顺位题号是938).给定二叉搜索树的根节点,返回节点值在[L,R]之间的所有节点的值的总和.二叉搜索树的节点值唯一.例如: 输入:root = [10,5,15,3,7,null,18],L = 7,R = 15 输出:32 输入:root = [10,5,15,3,7,13,18,1,null,6],L = 6,R = 10 输出:23 注意: 树中的节点数最多为1000…

1.原题: https://leetcode.com/problems/range-sum-of-bst/ Given the root node of a binary search tree, return the sum of values of all nodes with value between L and R (inclusive). The binary search tree is guaranteed to have unique values. Input: root =…

Given the root node of a binary search tree, return the sum of values of all nodes with value between L and R (inclusive). The binary search tree is guaranteed to have unique values. Example 1: Input: root = [10,5,15,3,7,null,18], L = 7, R = 15 Outpu…

给定二叉搜索树的根结点 root,返回 L 和 R(含)之间的所有结点的值的和. 二叉搜索树保证具有唯一的值. 示例 1: 输入:root = [10,5,15,3,7,null,18], L = 7, R = 15 输出:32 示例 2: 输入:root = [10,5,15,3,7,13,18,1,null,6], L = 6, R = 10 输出:23 提示: 树中的结点数量最多为 10000 个. 最终的答案保证小于 2^31. 二叉树有关的一般都是递归求解 class Solution…