121. Best Time to Buy and Sell Stock Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algor…
121. Best Time to Buy and Sell Stock 题目的要求是只买卖一次,买的价格越低,卖的价格越高,肯定收益就越大 遍历整个数组,维护一个当前位置之前最低的买入价格,然后每次计算当前位置价格与之前最低价格的差值,获得最大差值即为结果 class Solution { public: int maxProfit(vector<int>& prices) { if(prices.empty()) ; ]; ; ;i < prices.size();i++){…
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. Exam…
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (i.e., buy one and sell one share of the stock), design an algorithm to find the maximum profit. No…
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (i.e., buy one and sell one share of the stock), design an algorithm to find the maximum profit. No…
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. Exam…
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. 解题思路…
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. Exam…
题目描述: Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit…
题目描述 已知一个数组,第i个元素表示第i天股票的价格,你只能进行一次交易(买卖各一次),设计算法找出最大收益 测试样例 Input: [7, 1, 5, 3, 6, 4] Output: 5 最大收益 = 6-1 = 5 (不是7-1 = 6,因为先买后卖,7买,1买亏了6) Input: [7, 6, 4, 3, 1] Output: 0 最大收益为0 详细分析 初看非常简单,遍历数组,每次选择一个元素,找到这个元素后面的数组的最大值,计算差值,和当前最大收益比较即可,就像这样: [7,1,…