D. Little Artem and Dance 题目连接: http://www.codeforces.com/contest/669/problem/D Description Little Artem is fond of dancing. Most of all dances Artem likes rueda - Cuban dance that is danced by pairs of boys and girls forming a circle and dancing tog…

B. Little Artem and Dance time limit per test 2 second memory limit per test 256 megabytes input standard input output standard output Little Artem is fond of dancing. Most of all dances Artem likes rueda - Cuban dance that is danced by pairs of boys…

题目链接:http://codeforces.com/problemset/problem/669/D D. Little Artem and Dance time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Little Artem is fond of dancing. Most of all dances Artem like…

题目链接: D. Little Artem and Dance time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Little Artem is fond of dancing. Most of all dances Artem likes rueda — Cuban dance that is danced by pairs…

题目链接: Codeforces 669D Little Artem and Dance 题目描述: 给一个从1到n的连续序列,有两种操作: 1:序列整体向后移动x个位置, 2:序列中相邻的奇偶位置互换. 问:q次操作后,输出改变后的序列? 解题思路: 刚开始只看了第一组样例,发现相邻的奇偶位一直在一起,于是乎就开始writing code,写完后发现并不是正解!!!!就去推了一下第三个样例,总是这组实例通过,那组实例卡死,,,,,,,最后终于成功的Mengbility.今天突然想起来,其实整体…

D. Little Artem and Dance Little Artem is fond of dancing. Most of all dances Artem likes rueda - Cuban dance that is danced by pairs of boys and girls forming a circle and dancing together. More detailed, there are n pairs of boys and girls standing…

题目链接: http://codeforces.com/contest/669/problem/D 题意: 给你一个初始序列:1,2,3,...,n. 现在有两种操作: 1.循环左移,循环右移. 2.1,2位置交换,3,4位置交换,...,n-1,n位置交换 现在问执行了q次操作之后序列是什么,每次操作可以是两种操作的任意一种 题解: 我们把数列按位置的奇偶分为两堆,无论哪种操作,始终都还是这两堆,最多就是整堆的对换和一个堆内部的偏移. 所以我们只要记录第一个位置和第二个位置的数的变化(相当于每…

模拟. 每个奇数走的步长都是一样的,每个偶数走的步长也是一样的. 记$num1$表示奇数走的步数,$num2$表示偶数走的步数.每次操作更新一下$num1$,$num2$.最后输出. #pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #i…

题意:2种操作,转动或者奇偶位互换. 不论怎么交换,1的后两位一定是3,3的后两位一定是5.因此只要记录1,2的位置. //#pragma comment(linker,"/STACK:1024000000,1024000000") #include<iostream> #include<cstdio> #include<string> #include<cstring> #include<vector> #include&l…

http://codeforces.com/problemset/problem/669/D 题意:n个数1~N围成一个圈.q个操作包括操作1:输入x, 所有数右移x.操作2:1,2位置上的数(swap(a[1], a[2])交换:3,4交换.... 题解:观察,发现所有奇数行为都是一样的,偶数同理,(对于操作1 两者相同,对于操作2 奇数位++,偶数位上--: 模拟1,2,即可,然后依次输出其它数字即可.(看清 ac代码: #define _CRT_SECURE_NO_WARNINGS #in…