Implement strStr(). Returns a pointer to the first occurrence of needle in haystack, or null if needle is not part of haystack. 就是判断haystack中是否有needle,如果包含的话,返回第一次包含的地址.如果没有则返回NULL. 这题官网打出来的是easy,但是要做好绝不简单.我能想到的就是O(m*n)的复杂度了.最经典的是用KMP算法. class Soluti…
# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 28: Implement strStr()https://oj.leetcode.com/problems/implement-strstr/ Implement strStr().Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of h…
Implement strStr() Implement strStr(). Returns a pointer to the first occurrence of needle in haystack, or null if needle is not part of haystack. 解法一:暴力解 class Solution { public: int strStr(string haystack, string needle) { int m = haystack.size();…
Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 额,当然我用的就是暴力搜索来,没用到KMP之类的算法,有时间再来补上辣,代码如下: class Solution { public: int strStr(string haystack, string needle) { ; ; ; i <= h…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 find函数 遍历+切片 日期 题目地址:https://leetcode.com/problems/implement-strstr/description/ 题目描述 Implement strStr(). Return the index of the first occurrence of needle in haystack, or -1…
一天一道LeetCode系列 (一)题目 Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. (二)解题 第一种解法:朴素匹配算法 /* 两个指针,分别指向两个字符串的首字符 如果相等则一起向后移动,如果不同i取第一个相同字符的下一个开始继续匹配 如果最后j等于needle的长度则匹配成功,返回i-…
https://leetcode.com/problems/implement-strstr/ 题目: Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 思路: 判断一个string是否另一个string的子序列并返回位置. naive法:遍历查找,复杂度O(mn). advance法还有Rabi…
Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Solution: class Solution { public: int strStr(string haystack, string needle) { //runtime:4ms int len1=haystack.size(), len…
