Problem Description A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multiple test cases. Each test case co…

原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=1005 主要内容: A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). 看到这样的公式很容易想到递归调用求解,但是在本题中n的取…

Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multiple test cases. Each test case…

Problem Description A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test cases. Each test case co…

#include "iostream" using namespace std; int fun(int A,int B,int n) { ,y = ,z; || n == ) ; else { z = (A*y +B*x )%; ;i<n;i++) { int t = z; z = (A*z +B*y )%; x = y; y = t; } return y; } } int main() { int A,B,n; ]; ; cin >> A >> B…