LeetCode 336. Palindrome Pairs】的更多相关文章

原题链接在这里:https://leetcode.com/problems/palindrome-pairs/ 题目: Given a list of unique words, find all pairs of distinct indices (i, j) in the given list, so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Example 1:Giv…
https://leetcode.com/problems/palindrome-pairs/ Given a list of unique words. Find all pairs of distinct indices (i, j) in the given list, so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Example 1: Given words =…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 HashTable 相似题目 参考资料 日期 题目地址:https://leetcode.com/problems/palindrome-pairs/description/ 题目描述 Given a list of unique words, find all pairs of distinct indices (i, j) in the give…
Given a list of unique words, find all pairs of distinct indices (i, j) in the given list, so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Example 1: Input: ["abcd","dcba","lls","s&q…
lc132 Palindrome Pairs 2 大致与lc131相同,这里要求的是最小分割方案 同样可以分割成子问题 dp[i][j]还是表示s(i~j)是否为palindrome res[i]则用来记录s(0~i)的最小cut数 class Solution { public int minCut(String s) { int[] dp = new int[s.length()]; boolean[][] isP = new boolean[s.length()][s.length()];…
lc131 Palindrome Pairs 解法1: 递归 观察题目,要求,将原字符串拆成若干子串,且这些子串本身都为Palindrome 那么挑选cut的位置就很有意思,后一次cut可以建立在前一次cut的基础上 举例来说 "aab" 第一次cut"a" "ab" 第二次cut"a" "b" 很容易总结出规律,s(i, j)被i=<k<j,截断 若s(i,k)本身就是palindrome,那…
1. Description Given a list of unique words. Find all pairs of distinct indices (i, j) in the given list, so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Example 1: Given words = ["bat", "tab", &qu…
题目如下: 解题思路:对于任意一个word,要找出在wordlist中是否存在与之能组成回文的其他words,有两种思路.一是遍历wordlist:二是对word本身进行分析,找出能组成回文的words,并判断是否存在于wordlist中.显然,第二种思路比较的次数要少很多.怎么找出能组成回文的words呢?只要把后面的字符依次往前复制,并判断是否为回文,直到全部字符复制完成为止,这就能得到所有能与之组成回文的words.以abcd作为前缀为例,首先把d复制到abcd前面得到dabcd,接下来依…
Given a list of unique words, find all pairs of distinct indices (i, j) in the given list, so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Example 1:Given words = ["bat", "tab", "cat"]Ret…
给定一组独特的单词, 找出在给定列表中不同 的索引对(i, j),使得关联的两个单词,例如:words[i] + words[j]形成回文.示例 1:给定 words = ["bat", "tab", "cat"]返回 [[0, 1], [1, 0]]回文是 ["battab", "tabbat"]示例 2:给定 words = ["abcd", "dcba", &q…