题目大意:空间中有许多无限长的棒子(圆柱体),求棒子间最小距离. #include <iostream> #include <cstdio> #include <cstring> #include <cmath> using namespace std; ; struct Point3//三维空间点 { double x, y, z; Point3(,,): x(x),y(y),z(z){} Point3 operator + (Point3 &t)…

Weapon Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 270    Accepted Submission(s): 212 Problem Description Doctor D. are researching for a horrific weapon. The muzzle of the weapon is a circ…

转载学习: #include <cstdio> #include <cstdlib> #include <cstring> #include <algorithm> #include <cmath> using namespace std; ; ; struct Point3 //空间点 { double x, y, z; Point3( , , ): x(x), y(y), z(z) { } Point3( const Point3&…

Save Labman No.004 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 624    Accepted Submission(s): 154 Problem Description Due to the preeminent research conducted by Dr. Kyouma, human beings hav…

题目: http://acm.hdu.edu.cn/showproblem.php?pid=4312 Meeting point-2 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1231    Accepted Submission(s): 691 Problem Description It has been ten years s…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=4311 Meeting point-1 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3426    Accepted Submission(s): 1131 Problem Description It has been ten years s…

题目链接 这是HDU第400个题. #include <cstdio> #include <cstring> #include <set> #include <iostream> using namespace std; ],qur[][]; int main() { int i,j,k,n,m,num; while(scanf("%d%d",&n,&m)!=EOF) { multiset<]; multiset&l…

思路:这题我是看了题目后,上百度搜了一下才知道还有求最大曼哈顿距离的方法.直接把代码copy过来,研读一下,知道了代码实现机制,自然就很容易想到用优先队列来维护每种状态下的xi,yi之和的最大值最小值,以及其属于哪个点.那么对于删点操作只需要标记为不存在就可以了.在队列出队时,若队顶元素不存在,就出队. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm>…

这题难度颇大啊,TLE一天了,测试数据组数太多了.双向广度优先搜索不能得到字典序最小的,一直WA. 思路:利用IDA*算法,当前状态到达目标状态的可能最小步数就是曼哈顿距离,用于搜索中的剪枝.下次搜索的限制不能直接加1,会超时,应该从当前状态到目标状态最小限制开始搜索. AC代码 #include<cstdio> #include<cstring> #include<algorithm> #include<iostream> #include<cmat…

题目链接 这题,明显考察搜索能力...在中文版的维基百科中找到了公式. #include <cstdio> #include <cstring> #include <string> #include <algorithm> using namespace std; #define MOD 1000000007 #define LL __int64 LL dp[]; ],flag[]; int main() { int i,n,t,j,num; LL x; n…