题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=5344 #include<stdio.h> #include<cstring> ; int A[MAXN]; void bas( int n, int m, int z, int l){ ;i < n; ++i){ A[i] = ( (]*m + z )% l; } } void Cal(int n){ ; ;i < n; ++i){ sum = sum ^ (A[i]*);…

Problem Description   MZL loves xor very much.Now he gets an array A.The length of A ≤i,j≤n) The xor of an array B is defined as B1 xor B2...xor Bn Input Multiple test cases, the first line contains an integer T(no more than ), indicating the number…

MZL's xor Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 911    Accepted Submission(s): 589 Problem Description MZL loves xor very much.Now he gets an array A.The length of A is n.He wants to k…

MZL's xor Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 249    Accepted Submission(s): 187 Problem Description MZL loves xor very much.Now he gets an array A.The length of A is n.He wants to k…

题意:给一个序列A,设序列B的中的元素有(Ai+Aj)(1≤i,j≤n),那么求B中所有元素的异或之和.而序列A是这样来的:A1=0,Ai=(Ai−1∗m+z) mod l. 思路:相同的元素异或结果为0,所以可以去掉,也就是剩下A中的元素ai+ai那些而已. 小心乘法会溢出 #include <bits/stdc++.h> #define INF 0x7f7f7f7f #define pii pair<int,int> #define LL long long using nam…

转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud MZL's xor Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 488    Accepted Submission(s): 342 Problem Description MZL loves xor very muc…

MZL's xor Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/65536K (Java/Other) Total Submission(s) : 1   Accepted Submission(s) : 1 Problem Description MZL loves xor very much.Now he gets an array A.The length of A is n.He wants to know t…

题目传送门 /* 题意:给一个n个点,m条边的无向图,要求给m条边定方向,使得每个定点的出入度之差的绝对值小于等于1. 输出任意一种结果 图论:一个图,必定存在偶数个奇度顶点.那么从一个奇度定点深搜,当碰到另外一个奇度顶点时结束,这样能保证度数差<=1 3.5 详细解释:http://blog.csdn.net/ZSGG_ACM/article/details/47287681 */ /************************************************ * Auth…

题目传送门 /* 这题可以用stl的mutiset容器方便求解,我对这东西不熟悉,TLE了几次,最后用读入外挂水过. 题解有O(n)的做法,还以为我是侥幸过的,后来才知道iterator it写在循环内才超时了,囧! */ /************************************************ Author :Running_Time Created Time :2015-8-4 12:10:11 File Name :G.cpp ******************…

MZL's xor Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 800    Accepted Submission(s): 518 Problem Description MZL loves xor very much.Now he gets an array A.The length of A is n.He wants to…