Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 分析:题意为 给定一个有序整型数组,返回总结区间,具体来说就是找出连续的序列,然后首尾两个数字之间用个“->"来连接,那么只需遍历一…

Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…

Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 就是概括区间的方式把一个数组表示下来,例如123用1->3代替,自己写的很乱 ,维护两个指针就可以了: class Solution { pu…

Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Example 2: Input: [0,2,3,4,6,8,9] Output: ["0","2->4"…

Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 解题思路: JAVA实现如下: public List<String> summaryRanges(int[] nums) { List…

Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. Credits:Special thanks to @jianchao.li.fighter for adding this problem and…

题目描述: Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 解题思路: 相邻的两个数字若差距为1,则继续向后读,直到不满足条件为止,则把起始到终点的结果表示出来.如此,直到读到数组的最后位置为止.…

Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 我的代码,结果Accepted,507ms: public class Solution { public IList<string>…

Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…

Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. class Solution { public: vector<string> summaryRanges(vector<int&…