题目:一个有序数组,要求保证数组中的每个元素不能超过2个.  输入:A = [1,1,1,2,2,3]  输出:length = 5, and A is now [1,1,2,2,3] 思路:双指针 .有些绕,不过理清了后,思路还是很直接明朗的. 1.两个指针:p和help.初始化时同时指向数组头.变量cur记录当前元素值,count记录当前元素值出现的次数. 2.当 A[p] == cur && count < 2 或者 A[p] != cur 的时候,A[help] = A[p]…

Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A = [1,1,1,2,2,3], Your function should return length = 5, and A is now [1,1,2,2,3]. 这道题是之前那道Remove Duplicates from Sorted Array 有序数组中…

题目: Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A = [1,1,1,2,2,3], Your function should return length = 5, and A is now [1,1,2,2,3]. Tag: Array; Two Pointers 体会: 继续是quicksort中par…

Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A =[1,1,1,2,2,3], Your function should return length =5, and A is now[1,1,2,2,3]. 题意:可以保留一个重复的元素. 思路:第一种是和Remove duplicates from sorte…

题目 Follow up for "Remove Duplicates": What if duplicates are allowed at most twice? For example, Given sorted array A = [1,1,1,2,2,3], Your function should return length = 5, and A is now [1,1,2,2,3]. 原题链接(点我) 解题思路 移除数组中反复次数超过2次以上出现的数,可是能够同意反复2次…

原题地址:https://oj.leetcode.com/problems/remove-duplicates-from-sorted-array-ii/ 题意: Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A = [1,1,1,2,2,3], Your function should return lengt…

class Solution { public: int removeDuplicates(int A[], int n) { ],*e=&A[]; //s指向“连续数字”的第一个,e往后遍历相同的 ,j=n; ;i<n;i++){ e++; ) ){ //新的数字,直接加复制到s处 if(*s==*e) flag=; else flag=; s++; *s=*e; } else j--; } return j; } }; 题意:提供一个整型数组,和该数组内有n个元素,数组已经有序.相同的数…

LeetCode:Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constan…

LeetCode 80 Remove Duplicates from Sorted Array II [Array/auto] <c++> 给出排序好的一维数组,如果一个元素重复出现的次数大于两次,删除多余的复制,返回删除后数组长度,要求不另开内存空间. C++ 献上自己丑陋无比的代码.相当于自己实现一个带计数器的unique函数 class Solution { public: int removeDuplicates(std::vector<int>& nums) {…

Remove Duplicates from Sorted Array II Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A = [1,1,1,2,2,3], Your function should return length = 5, and A is now [1,1,2,2,3].     用两个指针,…