Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and fiv…

https://leetcode.com/problems/fizz-buzz/ 没什么好说的,上一个小学生解法 class Solution(object): def fizzBuzz(self, n): l=[] for x in xrange(1, n+1): if x%15==0: l.append("FizzBuzz") elif x%3==0: l.append("Fizz") elif x%5==0: l.append("Buzz"…

------------------------ AC代码: class Solution { /** * param n: As description. * return: A list of strings. */ public ArrayList<String> fizzBuzz(int n) { ArrayList<String> results = new ArrayList<String>(); for (int i = 1; i <= n; i++…

Problem: Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output "Fizz" instead of the number and for the multiples of five output "Buzz". For numbers which are multipl…

-------------------------------------------- 虽然是从最简单的开始刷起,但木有想到LeetCode上也有这么水的题目啊... AC代码: public class Solution { public List<String> fizzBuzz(int n) { List<String> res=new ArrayList<>(); for(int i=1;i<=n;i++){ if(i/3*3==i &&…

原题链接在这里:https://leetcode.com/problems/fizz-buzz/ 题目: Write a program that outputs the string representation of numbers from 1 to n. But for multiples of three it should output "Fizz" instead of the number and for the multiples of five output &qu…

给你一个字符串和字典,从头扫到位,如果到当前的字符的字符串存在于字典中,则显示 buzz. 例子: ILOVEPINEAPPLEJUICE 字典: [pine, apple, pineapple, juice, applejuice] 那么当我们到达ILOVEPINE的时候,就要buzz,当我们到达APPLE的时候,也要buzz,当我们到达JUICE的时候,也要buzz. public class Solution { public static void main(String[] args)…

class Solution { public: /** * param n: As description. * return: A list of strings. */ vector<string> fizzBuzz(int n) { vector<string> results; ; i <= n; i++) { == ) { results.push_back("fizz buzz"); } == ) { results.push_back(&q…

下面是AC代码,C++风格: class Solution { public: vector<string> fizzBuzz(int N) { vector<string> Answer; ;i <= N;i++) { == ) { Answer.push_back("fizz buzz"); } == ) { Answer.push_back("fizz"); } == ) { Answer.push_back("buzz…

写一段程序从1打印到100,但是遇到3的倍数时打印Fizz,遇到5的倍数时打印Buzz,遇到即是3的倍数同时也是5的倍数时打印FizzBuzz.例如: 1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz 16 17 Fizz 19 Buzz ... 等等,直到 100…