程序: 1 #include <stdio.h> 2 #define MaxTree 10 3 #define ElementType char 4 #define Tree int 5 #define Null -1 6 7 struct TreeNode { 8 ElementType Element; 9 Tree Left; 10 Tree Right; 11 } T1[MaxTree],T2[MaxTree]; 12 int N,check[MaxTree]; 13 14 Tree…

Tree Traversals Suppose that all the keys in a binary tree are distinct positive integers. Given the postorder and inorder traversal sequences, you are supposed to output the level order traversal sequence of the corresponding binary tree. Input Spec…

用栈实现树遍历 1 #include<stdio.h> 2 #include<string.h> 3 #define MAXSIZE 30 4 5 int Pre[MAXSIZE],In[MAXSIZE],Post[MAXSIZE]; 6 void solve(int preL,int inL,int postL,int n); 7 void outPut(int p[],int n); 8 9 int main(){ 10 int n,tmp,i,j = 0; 11 int to…

1.  minimum-depth-of-binary-tree 题目描述 Given a binary tree, find its minimum depth.The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 求二叉树的最小深度:   解题思路 递归遍历二叉树的每一个节点: (1)如果该节点为null,返回深度为0…

Given a binary tree, flatten it to a linked list in-place. For example,Given 1 / \ 2 5 / \ \ 3 4 6 The flattened tree should look like: 1 \ 2 \ 3 \ 4 \ 5 \ 6 Hints: If you notice carefully in the flattened tree, each node's right child points to the…

程序: 1 #include <stdio.h> 2 #include <stdlib.h> 3 typedef struct TreeNode *Tree; 4 struct TreeNode{ 5 int v; 6 Tree Left,Right; 7 int flag; 8 }; 9 Tree NewNode(int V){ 10 Tree T=(Tree)malloc(sizeof(struct TreeNode)); 11 T->v = V; 12 T->Le…

1119 Pre- and Post-order Traversals (30 分) Suppose that all the keys in a binary tree are distinct positive integers. A unique binary tree can be determined by a given pair of postorder and inorder traversal sequences, or preorder and inorder travers…

Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. 类似http://www.cnblogs.com/sunshineatnoon/p/3854935.html 只是子树的前序和中序遍历序列分别更新为: //左子树: left_prestart = prestart+1 lef…

题目: 7-63 查验身份证 (15 分)  一个合法的身份证号码由17位地区.日期编号和顺序编号加1位校验码组成.校验码的计算规则如下: 首先对前17位数字加权求和,权重分配为:{7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2}:然后将计算的和对11取模得到值Z:最后按照以下关系对应Z值与校验码M的值: Z:0 1 2 3 4 5 6 7 8 9 10 M:1 0 X 9 8 7 6 5 4 3 2 现在给定一些身份证号码,请你验证校验码的有效性,并输出有问题的号码.…

Binary Tree Right Side View Given a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom. Example: Input: [1,2,3,null,5,null,4] Output: [1, 3, 4] Explanation: 1 <--- / \…