记$m=10$,即商品的种类 记$g(x)=1+\sum_{i=1}^{m}a_{i}x_{i}$,问题即求$f_{n}(x)=g^{n}(x)$非0项数(模2意义下) 注意到$f^{2}(x)\equiv f(x^{2})(mod\ 2)$,这是因为如果所选的项在两边不同,那么交换后即会抵消 令$F(n,A)$为$A(x)f_{n}(x)$非0项数,即有$\begin{cases}F(n+1,A)=F(n,A\cdot g)\\F(2n,A)=F(n,E)+F(n,O)\end{cases}$…

Description 这道题的题意是这道难读,大概就是给你n个商店,每个商店的重量为i的商品用ai表示,对于任意商店的a数列都是相同的,重量的范围为[1,10] 求购买方案总数为奇数的重量一共有多少种,答案取膜998244353 Input Format 多组数据,每组数据第一行一个整数n表示一共有n个商店,第二行10个整数表示数列a Output Format 对于每组数据输出一行表示答案 Sample Input 1 1 2 3 4 5 6 7 8 9 10 2 1 0 0 0 0 0 0…

A - Absolute 留坑. B - Counting Permutations 留坑. C - Cover 留坑. D - Game puts("Yes") #include <bits/stdc++.h> using namespace std; int n; int main() { while (scanf("%d", &n) != EOF) { puts("Yes"); } ; } E - Hack It 留坑.…

觉得有必要在NOI之前开一篇学习内容记录. 至于为什么要取这个标题呢?也许并没有什么特殊的借口吧. 5.23 在LOJ上搬了三道原题给大家考了考,然后大家都在考试就我一个人在划水. SSerxhs 和 Serval 的退役纪念赛 A.幼儿园唱歌题 给一个串\(S\),\(q\)次询问满足是串\(S[l_1,r_1]\)的前缀且是串\(S[l_2,r_2]\)的后缀的最长回文串长度.\(|S|,q\le2\times10^5\) 把串\(S\)反过来接在后面建回文树,然后就是求两个点的公共祖先中深…

Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes. You should try to do it in place. The program should run in O(1) space complexi…

Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes. You should try to do it in place. The program should run in O(1) space complexi…

Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes. You should try to do it in place. The program should run in O(1) space complexi…

:even匹配所有索引值为偶数的元素,从 0 开始计数查找表格的1.3.5...行(即索引值0.2.4...)<table> <tr><td>Header 1</td></tr> <tr><td>Value 1</td></tr> <tr><td>Value 2</td></tr></table> $("tr:even"…

Given a singly linked list, group all odd nodes together followed by the even nodes. Please note here we are talking about the node number and not the value in the nodes. The program should run in O(1) space complexity and O(nodes) time complexity. E…

nth-child(odd):奇数 nth-child(even):偶数 使用时,如果是精确到数字时,切记是从同一级别的元素开始计算,而不是指定某个类才开始计算. 比如: <li></li> <li class="test"></li> <li></li> 如果我要选择class为test的,nth-child(2),第2个. 详细解释,参考: http://niutuku.com/tech/css/249737.…