水题,输出的时候注意下 #include <stdio.h> #include <math.h> int main() { int d; scanf("%d",&d); while(d--) { ]; ; scanf("%d",&n); ) { binary[i++]=n%; n/=; } ; ;j<i;j++) { if(binary[j]) { printf("%d",j); ) printf(&…

Binary Numbers Time Limit: 2 Seconds      Memory Limit: 65536 KB Given a positive integer n, print out the positions of all 1's in its binary representation. The position of the least significant bit is 0. Example The positions of 1's in the binary r…

属于水题,主要是涉及到回文问题. 这里标注下进制转换的方法: while(n) { p[i]=n%basis; n/=basis; } 见代码: #include <stdio.h> int revert(int n,int base) { int p[20]; int i=0; while(n) { p[i++]=n%base; n/=base; } int ispar=1; for(int j=0,k=i-1;j<k;j++,k--) { if(p[j]!=p[k]) { ispar…

http://acm.hdu.edu.cn/showproblem.php?pid=1390 Binary Numbers Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2298    Accepted Submission(s): 1460 Problem Description Given a positive integer n…

Binary Numbers 点我 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3820    Accepted Submission(s): 2321 Problem Description Given a positive integer n, find the positions of all 1's in its binary…

E. Binary Numbers AND Sum 题目链接:https://codeforces.com/contest/1066/problem/E 题意: 给出两个用二进制表示的数,然后将第二个二进制不断地往右边移一位,每次答案加上这两个的交集,求最后的答案. 题解: 考虑第二个二进制每一位对答案的贡献就行了,然后对第一个二进制算前缀和就ok了. 代码如下: #include <bits/stdc++.h> using namespace std; typedef long long l…

problem 1022. Sum of Root To Leaf Binary Numbers 参考 1. Leetcode_easy_1022. Sum of Root To Leaf Binary Numbers; 完…

  ZOJ Problem Set - 1090 The Circumference of the Circle Time Limit: 2 Seconds      Memory Limit: 65536 KB To calculate the circumference of a circle seems to be an easy task - provided you know its diameter. But what if you don't? You are given the…

这道题目还是简单的,但是自己WA了好几次,总结下: 1.对输入的总结,加上上次ZOJ Problem Set - 1334 Basically Speaking ac代码及总结这道题目的总结 题目要求输入的格式: START X Y Z END 这算做一个data set,这样反复,直到遇到ENDINPUT.我们可以先吸纳一个字符串判断其是否为ENDINPUT,若不是进入,获得XYZ后,吸纳END,再进行输出结果 2.注意题目是一个圆周,所以始终用锐角进行计算,即z=360-z; 3.知识点的误…

ZOJ Problem Set - 1025 题目分类:基础题 原题地址:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=1025   题目大意就是有很多木头,都有各自的长度和重量.现在要加工这些木头,如果加工某根木头的长度和重量大于等于它上一根木头的长度和重量,那么加工它不需要时 间,否则要花1分钟.现给出一堆木头的长度和重量,要求加工完这堆木头可以花的最少时间.例如给出5根木头长度重量分别为(4,9), (5,2),…